All categories

3 years ago

Need help answering

Mathematics

2 answers:

Alenkasestr [34]3 years ago

5 0

I thinks it’s 9 or 11

adelina 88 [10]3 years ago

4 0

I think the answer is 11

You might be interested in

HELP ME PLS if y varies inversely with x, and y = 15/2 when x = 4, find x when y = 15/4

SCORPION-xisa [38]

Y=1/x
y=k/x
Where “k” is a constant
15/2=k/4
2k=60
k=60/2
k=30
:. 15/4=30/x
15x=120
x=120/15
:.x=8.

8 0

3 years ago

Passes through the points (−4, 2) and (12, 6)?

svlad2 [7]

I'll assume you need to find the equation of the line that passes through those points.

Answer:

$\displaystyle y-2=\frac{1}{4}(x+4)$

Step-by-step explanation:

Equation of a Line:

The equation of a line passing through points (x1,y1) and (x2,y2) can be found as follows:

$\displaystyle y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

The given points are (-4,2) and (12,6), thus:

$\displaystyle y-2=\frac{6-2}{12+4}(x+4)$

Operating:

$\displaystyle y-2=\frac{4}{16}(x+4)$

Simplifying, the equation in point-slope form is:

$\mathbf{\displaystyle y-2=\frac{1}{4}(x+4)}$

3 0

3 years ago

Which point lies on a circle with a radius of 5 units and center at P(6,1)?

ryzh [129]

Answer:

Option B. $R(2,4)$

Step-by-step explanation:

we know that

If a ordered pair lie on the circle. then the ordered pair must satisfy the equation of the circle

step 1

Find the equation of the circle

we know that

The equation of the circle in center radius form is equal to

$(x-h)^{2}+(y-k)^{2}=r^{2}$

where

r is the radius of the circle

(h,k) is the center of the circle

substitute the values

$(x-6)^{2}+(y-1)^{2}=5^{2}$

$(x-6)^{2}+(y-1)^{2}=25$

step 2

Verify each case

case A) $Q(1, 11)$

substitute the value of $x=1, y=11$ in the equation of the circle and then compare the results

$(1-6)^{2}+(11-1)^{2}=25$

$25+100=25$ ------> is not true

therefore

the ordered pair Q not lie on the circle

case B) $R(2,4)$

substitute the value of $x=2, y=4$ in the equation of the circle and then compare the results

$(2-6)^{2}+(4-1)^{2}=25$

$16+9=25$ ------> is true

therefore

the ordered pair R lie on the circle

case C) $S(4,-4)$

substitute the value of $x=4, y=-4$ in the equation of the circle and then compare the results

$(4-6)^{2}+(-4-1)^{2}=25$

$4+25=25$ ------> is not true

therefore

the ordered pair S not lie on the circle

case D) $T(9,-2)$

substitute the value of $x=4, y=-4$ in the equation of the circle and then compare the results

$(9-6)^{2}+(-2-1)^{2}=25$

$9+9=25$ ------> is not true

therefore

the ordered pair T not lie on the circle

7 0

3 years ago

Good afternoon and god bless guys!! Does anyone knows the answer to this?

Nastasia [14]

Answer:

Step-by-step explanation:

3 0

3 years ago

For the following set of 20 numbers:

patriot [66]

Answer:

I cannot answer all of this, so I will only answer what I can:

Q1: 13

Q3: 22.5

IQR: 13.5

IQR(1.5): 20.25

Q3 + IQR(1.5) = 43

Q1 - IQR(1.5) = -7.25

I don't know if my calculations are all right but I hope this helps! :)

4 0

3 years ago

Need help answering ​

Need help answering