Question

Help please ..........

Answer 1

Answer:

m∠1 = 30°

Step-by-step explanation:

Properties of a rhombus,

1). Sum of adjacent angles is 180°.

2). Diagonals bisects the angles of a rhombus

By property - (1)

m∠M + m∠N = 180°

120° + m∠N = 180°

m∠N = 180 - 120

         = 60°

By property - (2)

Diagonal PM will bisect the angle M.

m∠1 = m∠2

m∠1 = $\frac{1}{2}(\angle N)$

       = $\frac{1}{2}(60)$

       = 30°