Answer:
-13, -3
15, 2.6
Step-by-step explanation:
x, y are the numbers
x = 5y + 2
x×y = 39
(5y + 2)×y = 39
5y² + 2y - 39 = 0
the solution of a quadratic equation :
y = (-b ± sqrt(b² - 4ac))/2a
a = 5
b = 2
c = -39
y = (-2 ± sqrt(2² - 4×5×-39))/2×5 =
= (-2 ± sqrt(4 + 780))/10 =
= (-2 ± sqrt(784))/10 = (-2 ± 28)/10
y1 = (-2 + 28)/10 = 26/10 = 2.6
y2 = (-2 - 28)/10 = -30/10 = -3
x1 = 5×2.6 + 2 = 13 + 2 = 15
x2 = 5×-3 + 2 = -15 + 2 = -13
Equation format for a slope, m and a point (x1, y1)
y - y1 = m(x - x1) (Try and memorize this formula)
8) for (3,-4), m = 6. x1 = 3, y1 = -4, Substituting
y - y1 = m(x - x1)
y - (-4) = 6(x - 3)
y + 4 = 6x - 18
y = 6x - 18 - 4
y = 6x - 22
10) for (-2,-7), m = 4/5. x1 = -2, y1 = -7, Substituting
y - y1 = m(x - x1)
y - (-7) = (4/5)*(x - (-2))
y + 7 = (4/5) *(x +2) 4/5 = 0.8
y + 7 = 0.8x + 1.6
y = 0.8x + 1.6-7
y = 0.8x - 6.4
y = (4/5)x - (64/10)
y = (4/5)x - (32/5)
So same approach to solve others. Cheers.
One over fifthteen...................................
Answer:
The rule is as follows:
x'=5*x
y'=5*y
Step-by-step explanation:
Each coordinate gets scaled by a factor of 5.
For example:
R(-2,0) --> R'(-10,0) [-2-->5*(-2), 0-->0]
and similarly with the other points S, T, and U
F (x) = |x+8|
F (-11) = |-11+8|
F (-11) = |-3|
F (-11) = 3
