Answer:
<em>The point lies barely outside of the circle</em>
Step-by-step explanation:
<u>Equation of a Circle</u>
Given its center (h,k) and radius r, the equation of a circle is given by
The circle given in the question is centered at (7,8) and has a radius of 6, thus its equation is
To find out if a point (a,b) is outside or inside the circle area, the following conditions apply.
if 
then the point lies outside of the circle area
if 
then the point lies inside of the circle area
Let's use the point as given (6,2)
Thus the point lies barely outside of the circle
Answer:
x=14/3
Step-by-step explanation:
5x-y=6
+ -2x+y=8
----------------
5x+(-2x)-y+y=6+8
5x-2x-y+y=6+8
3x=14
x=14/3
I apologize if something is incorrect, please me know how to fix it. Thank you!
The total amount of angles in quadrilateral is 360.so:
z=360-(122+79+90)
z=360-291
z=69
Answer:
12√3
Step-by-step explanation:
sin 30 =1/2
sin30=a/24. sin=opposit side/Hypotenuse
a is the opposite side of 30
1/2=a/24
a=12
now take pythagoras theroem
24^2=z^2+12^2
576=z^2+144
z^2=576-144
z^2=432
z=√432
z=√144*3
z=12√3
Of means multiplication and Is means equals. So 0.81x =405
X = 500
