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Anon25 [30]
3 years ago
6

What is an equation of the line that passes through the points (3, 1)(3,1) and (-3, -7)(−3,−7)?

Mathematics
1 answer:
rusak2 [61]3 years ago
3 0

Answer:

y = (4/3)x - 3

Step-by-step explanation:

What is an equation of the line that passes through the points (3, 1) and (-3,  -7)?  (Do not repeat the coordinates of the points.)

First we need to find the slope of the line through these two points.  From (-3, -7) to (3, 1), x increases by 6 (which is the 'run') and y increases from -7 to 1 ( a 'rise' of 8).  Thus, the slope of this line is m = rise/run = 8/6, or m = 4/3.

Using the point-slope formula as our starting point, we insert the known values m = 4/3 and point (3, 1):

y - k = m(x - h) becomes y - 1 = (4/3)(x - 3).  This in itself is a satisfactory answer.  We could also write this equation in slope-intercept form, as follows:

y = 1 + (4/3)x - 4, or

y = (4/3)x - 3

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Plzzzz help and I'll give you brainliest ​
sdas [7]

Step-by-step explanation:

Left hand side:

4 [sin⁶ θ + cos⁶ θ]

Rearrange:

4 [(sin² θ)³ + (cos² θ)³]

Factor the sum of cubes:

4 [(sin² θ + cos² θ) (sin⁴ θ − sin² θ cos² θ + cos⁴ θ)]

Pythagorean identity:

4 [sin⁴ θ − sin² θ cos² θ + cos⁴ θ]

Complete the square:

4 [sin⁴ θ + 2 sin² θ cos² θ + cos⁴ θ − 3 sin² θ cos² θ]

4 [(sin² θ + cos² θ)² − 3 sin² θ cos² θ]

Pythagorean identity:

4 [1 − 3 sin² θ cos² θ]

Rearrange:

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Double angle formula:

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Finally, apply Pythagorean identity and simplify:

4 − 3 (1 − cos² (2θ))

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