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Diano4ka-milaya [45]
3 years ago
9

A sample of air at 58.6 kPa is expanded from 250 mL to 655 mL. If thetemperature remains constant, what is the final pressure in

kPa?
Chemistry
1 answer:
kati45 [8]3 years ago
3 0

Answer:

<h2>22.366 kPa</h2>

Explanation:

The final pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the final pressure

P_2 =  \frac{P_1V_1}{V_2}  \\

From the question

58.6 kPa = 58600 Pa

We have

P_2 =  \frac{58600 \times 250}{655}  =  \frac{14650000}{655}  \\  = 22366.4122... \\  = 22366

We have the final answer as

<h3>22.366 kPa</h3>

Hope this helps you

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