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Jlenok [28]
3 years ago
12

9. During an experiment the students prepared three mixtures A)Starch in water B) Sodium chloride solution C) Tincture of Iodine

. i) Students observed a visible beam of light through mixture A. Why? ii) Tincture of lodTe did not show Tyndall effect. Explain reason. ill) How can you relate particle size to Tyndall effect?​
Chemistry
1 answer:
il63 [147K]3 years ago
7 0

Answer:

See explanation

Explanation:

Tyndall effect refers to the scattering of light in a solution. Tyndall effect occurs when the size of particles in the solution exceeds 1 nm in diameter. Such solutions are actually called false solutions.

In tincture of iodine, the size of particles in solution is less than 1 nm in diameter hence the solution does not exhibit Tyndall effect. Hence, tincture of iodine is a true solution.

Therefore, if the size of particles in solution exceeded 1nm in diameter, Tyndall effect is observed.

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sesenic [268]
2nd one is the awnser
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3 years ago
Carvone is a substance that occurs in two forms having different arrangements of the atoms but the same molecular formula (c10h1
Korvikt [17]

The molecular mass of Carvone is calculated as;

                          =  12 (C)₁₀  +  1.008 (H)₁₄  +  16 (O)

                          =  120  +  14.112  +  16

                          =  150.112

%age of Carbon;

                          =  (120 ÷ 150.112) × 100

                          =  79.94 %

%age of Hydrogen;

                          =  (14.112 ÷ 150.112) × 100

                          =  9.40 %

%age of Oxygen;

                          =  (16 ÷ 150.112) × 100

                          =  10.65 %

7 0
3 years ago
the heat of fusion of acetone is 5.7 kJ/mol. Calculate to two significant figures the entropy change when 6.3 mol of acetone mel
shtirl [24]

<u>Answer:</u> The entropy change of the process is 2.0\times 10^2J/K

<u>Explanation:</u>

To calculate the entropy change for different phase at same temperature, we use the equation:

\Delta S=n\times \frac{\Delta H_{f}}{T}

where,  

\Delta S = Entropy change

n = moles of acetone = 6.3 moles

\Delta H_{f} = enthalpy of fusion = 5.7 kJ/mol = 5700 J/mol    (Conversion factor:  1 kJ = 1000 J)

T = temperature of the system = -94.7^oC=[273-94.7]=178.3K

Putting values in above equation, we get:

\Delta S=\frac{6.3mol\times 5700J/mol}{178.3K}\\\\\Delta S=201.4J/K=2.0\times 10^2J/K

Hence, the entropy change of the process is 2.0\times 10^2J/K

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Answer:

The more spread out their energy becomes

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2 years ago
How many calories are required to heat 867 g of water from 13°c to 87°c?
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