Answer:
Explanation:
A. Attached is a page which contain the structural formula of the three compounds of C3H80.
Condensed structural formula of C3H8O:
Propan-1-ol: CH3CH2CH2OH
Propan-2-ol: CH3CH(OH)CH3
Methoxy methane: CH3OCH2CH3
B. Attached are is a page which contain the structural formula of the three compounds of C3H60.
Condensed structural formula of C3H6O:
Propanal: CH3CH2CHO
Propanone: CH3COCH3
Cyclopropanol: (C3H5)OH
2-propen-1-ol: CH2CHCH2OH
1-propenol: CH3CHCHOH
The element sodium has<span> 12 neutrons, </span>11<span> electrons and </span>11<span> protons.
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Answer:
2.5×10⁶ s
Explanation:
From the question given above, the following data were obtained:
Rate constant (K) = 2.8×10¯⁷ s¯¹
Half-life (t½) =?
The half-life of a first order reaction is given by:
Half-life (t½) = 0.693 / Rate constant (K)
t½ = 0.693 / K
With the above formula, we can obtain the half-life of the reaction as follow:
Rate constant (K) = 2.8×10¯⁷ s¯¹
Half-life (t½) =?
t½ = 0.693 / K
t½ = 0.693 / 2.8×10¯⁷
t½ = 2.5×10⁶ s
Therefore, the half-life of the reaction is 2.5×10⁶ s