an = a1+ d(n-1)
a1 =14
an=206 when n=25
206 = 14 + d (25-1)
206 = 14 + d * 24
subtract 14 from each side
192 = 24d
divide by 24 on each side
d=8
The common difference is 8
X = 78 degrees
Explanation:
Using the alternate exterior angle of 33 degrees, the angle to the left of x would also be 33 degrees
Using this we add up 69 and 33 = 102
Then we would do 180-102 since a straight line has a total of 180 degrees
The answer would be 78 degrees
Answer:
a) 4:3
b) 7:3
Step-by-step explanation:
No. of roses= 8
No. of daisies = 6
Total no. of flowers = 14
a) Ratio of roses to daisies = No. of roses/No. of daisies
8/6
= 4/3
= 4:3
b) Ratio of all flowers to daisies = No. of all flowers/ No. of daisies
14/6
= 7/3
= 7:3
5x + -4y = 13
Solving
-5x + -4y = 13
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '4y' to each side of the equation.
-5x + -4y + 4y = 13 + 4y
Combine like terms: -4y + 4y = 0
-5x + 0 = 13 + 4y
-5x = 13 + 4y
Divide each side by '-5'.
x = -2.6 + -0.8y
Simplifying
x = -2.6 + -0.8y
Simplifying
3x + -4y + -11 = 0
Reorder the terms:
-11 + 3x + -4y = 0
Solving
-11 + 3x + -4y = 0
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '11' to each side of the equation.
-11 + 3x + 11 + -4y = 0 + 11
Reorder the terms:
-11 + 11 + 3x + -4y = 0 + 11
Combine like terms: -11 + 11 = 0
0 + 3x + -4y = 0 + 11
3x + -4y = 0 + 11Combine like terms: 0 + 11 = 11
3x + -4y = 11
Add '4y' to each side of the equation.
3x + -4y + 4y = 11 + 4y
Combine like terms: -4y + 4y = 0
3x + 0 = 11 + 4y
3x = 11 + 4y
Divide each side by '3'.
x = 3.666666667 + 1.333333333y
Simplifying
x = 3.666666667 + 1.333333333y
Answer:
a. The distance from the center to either vertex
Step-by-step explanation:
The distance from the center to a vertex is the fixed value <em>a</em>. The values of <em>a</em> and <em>c</em> will vary from one ellipse to another, but they are fixed for any given ellipse.
I hope this helps you out alot, and as always, I am joyous to assist anyone at any time.