All categories

3 years ago

Plz help me what the coordinate points for each

Mathematics

1 answer:

krek1111 [17]3 years ago

6 0

Answer:

A. (-4, -3)

B. (5, 3)

C. (-1, 3)

Step-by-step explanation:

Ok, bear with me, its been a while since I have done this so make sure you double check.

A. So, we already know where point A is(1,-3) and we need that to find B

It says we need a reflection which is basically mirroring it across the y-axis(note: if it were across the x-axis then this would turn out much differently.)

Its hard to explain but i will tell you that reflecting point A will give us (-1, -3)

Now we need to translate it 3 units to the left

B. Ok, next we have point C which is a reflection using the x-axis (now you will see how important it is to make sure you are reflecting in the right place.) Over the x-axis, will give us (1, 3).

Now we need to translate to the right... (5, 3)

C. Point D... we need to rotate it. Now, rotating is a little bit more work than reflecting and translating but its not hard.

since we are rotating 180 degrees then we are basically just turning it around halfway from 360...

A is (1, -3) so D would be (-1, 3)

Hope this helps :)

You might be interested in

Find the directional derivative of the function at the given point in the direction of the vector v. f(x, y, z) = xey + yez + ze

attashe74 [19]

Answer: 6 / √26

Step-by-step explanation:

Given that f(x, y, z) = xe^y + ye^z + ze^x

so first we compute the gradient vector at (0, 0, 0)

Δf ( x, y, z ) = [ e^y + ze^x, xe^y + e^z, ye^z + e^x ]

Δf ( 0, 0, 0 ) = [ e⁰ + 0(e)⁰, 0(e)⁰ + e⁰, 0(e)⁰ + e⁰ ] = [ 1+0 , 0+1, 0+1 ] = [ 1, 1, 1 ]

Now we were also given that V = < 4, 3, -1 >

so ║v║ = √ ( 4² + 3² + (-1)² )

║v║ = √ ( 16 + 9 + 1 )

║v║ = √ 26

It must be noted that "v" is not a unit vector but since ║v║ = √ 26, the unit vector in the direction of "V" is ⊆ = ( V / ║v║)

⊆ = ( V / ║v║) = [ 4/√26, 3/√26, -1/√26 ]

therefore by equation D⊆f ( x, y, z ) = Δf ( x, y, z ) × ⊆

D⊆f ( x, y, z ) = Δf ( 0, 0, 0 ) × ⊆ = [ 1, 1, 1 ] × [ 4/√26, 3/√26, -1/√26 ]

= ( 1×4 + 1×3 -1×1 ) / √26

= (4 + 3 - 1) / √26

= 6 / √26

8 0

4 years ago

The number of defective circuit boards coming off a soldering machine follows a Poisson distribution. During a specific ten-hour

Alexus [3.1K]

Answer:

a) the probability that the defective board was produced during the first hour of operation is $\frac{1}{10}$ or 0.1000

b) the probability that the defective board was produced during the last hour of operation is $\frac{1}{10}$ or 0.1000

c) the required probability is 0.2000

Step-by-step explanation:

Given the data in the question;

During a specific ten-hour period, one defective circuit board was found.

Lets X represent the number of defective circuit boards coming out of the machine , following Poisson distribution on a particular 10-hours workday which one defective board was found.

Also let Y represent the event of producing one defective circuit board, Y is uniformly distributed over ( 0, 10 ) intervals.

f(y) = $\left \{ {{\frac{1}{b-a} }\\\ }} \right _0$ ; ( a ≤ y ≤ b ) $_{elsewhere$

= $\left \{ {{\frac{1}{10-0} }\\\ }} \right _0$ ; ( 0 ≤ y ≤ 10 ) $_{elsewhere$

f(y) = $\left \{ {{\frac{1}{10} }\\\ }} \right _0$ ; ( 0 ≤ y ≤ 10 ) $_{elsewhere$

Now,

a) the probability that it was produced during the first hour of operation during that period;

P( Y < 1 ) = $\int\limits^1_0 {f(y)} \, dy$

we substitute

= $\int\limits^1_0 {\frac{1}{10} } \, dy$

= $\frac{1}{10} [y]^1_0$

= $\frac{1}{10} [ 1 - 0 ]$

= $\frac{1}{10}$ or 0.1000

Therefore, the probability that the defective board was produced during the first hour of operation is $\frac{1}{10}$ or 0.1000

b) The probability that it was produced during the last hour of operation during that period.

P( Y > 9 ) = $\int\limits^{10}_9 {f(y)} \, dy$

we substitute

= $\int\limits^{10}_9 {\frac{1}{10} } \, dy$

= $\frac{1}{10} [y]^{10}_9$

= $\frac{1}{10} [ 10 - 9 ]$

= $\frac{1}{10}$ or 0.1000

Therefore, the probability that the defective board was produced during the last hour of operation is $\frac{1}{10}$ or 0.1000

no defective circuit boards were produced during the first five hours of operation.

probability that the defective board was manufactured during the sixth hour will be;

P( 5 < Y < 6 | Y > 5 ) = P[ ( 5 < Y < 6 ) ∩ ( Y > 5 ) ] / P( Y > 5 )

= P( 5 < Y < 6 ) / P( Y > 5 )

we substitute

$= (\int\limits^{6}_5 {\frac{1}{10} } \, dy) / (\int\limits^{10}_5 {\frac{1}{10} } \, dy)$

$= (\frac{1}{10} [y]^{6}_5) / (\frac{1}{10} [y]^{10}_5)$

= ( 6-5 ) / ( 10 - 5 )

= 0.2000

Therefore, the required probability is 0.2000

4 0

3 years ago

Canny plz help me out

Lostsunrise [7]

Answer: D) x ≥ -6

Step-by-step explanation:

It is greater than or equal to negative six because the circle is black, and not white with a white outline. The reason it's greater than is because it's going to the right, and going into greater numbers.

Hope this helps. HAVE A BLESSED AND WONDERFUL DAY! As well as a great Valentines Day! :-)

- Cutiepatutie ☺❀❤

3 0

4 years ago

Read 2 more answers

The amount of revenue in dollars, y, that Makayla receives from selling x posters is given by the equation y = 3x. The cost of p

d1i1m1o1n [39]

Answer:

75 posters

Step-by-step explanation:

Given

$y = 3x$ ---- Revenue

$y = \frac{x}{3} + 200$ --Cost of production

Required

Determine the number of posters that when cost equals revenue

To do this, we simply equate both equations

i.e. $3x = \frac{x}{3} + 200$

Collect like terms.

$3x - \frac{x}{3} = 200$

Multiply through by 3

$3(3x - \frac{x}{3}) = 200*3$

$9x - x = 600$

$8x = 600$

Divide both sides by 8

$\frac{8x}{8} = \frac{600}{8}$

$x = \frac{600}{8}$

$x = 75$

5 0

3 years ago

A small regional carrier accepted 21 reservations for a particular flight with 19 seats. 10 reservations went to regular custome

Viefleur [7K]

We have 19 available seats, and 21 reservations.

Of the 21 reservations, 10 are sure, so we have 10 out of the 19 seats that are surely occupied.

Then, we have 9 seats for 11 reservations, each one with 44% chance of being occupied.

We have to calculate the probability that the plane is overbooked. This means that more than 9 of the reservations arrive.

This can be modelled as a binomial distirbution with n = 11 and p = 0.44, representing the 44% chance.

Then, we have to calculate P(x > 9).

This can be calculated as:

$P(x>9)=P(x=10)+P(x=11)$

and each of the terms can be calculated as:

$\begin{gathered} P(x=10)=\dbinom{11}{10}\cdot0.44^{10}\cdot0.56^1=11\cdot0.0003\cdot0.56=0.0017 \\ P(x=11)=\dbinom{11}{11}\cdot0.44^{11}\cdot0.56^0=1\cdot0.0001\cdot1=0.0001 \end{gathered}$

Then: