<u>Problem</u>
A bag contains 6 blue marbles, 10 red marbles, and 9 green marbles. If two marbles are drawn at random without replacement, what is the probability that two red marbles are drawn?
<u>Work </u>
Probability = no. of favorable outcomes /total no. of outcomes
Probability of getting a blue marble=5/5+6+9=5/20
Probability of getting a red marble=6/20−1=6/19
5/20×6/19
<u>Answer</u>
3/20
So it is C.
Answer:
189
Step-by-step explanation:
You take 63% make it a decimal by dividing it by 100 and then you multiply it with 300. 300*.63=189.
0.405, 0.45 , 0.5 , 4.5 : Least to greatest!
Answer:
1.(1,5) and (2,6) , 6-5/2-1=1/1 m=1 ,y=1x+b
5=1(1)+b 4=b
y=x+4
2.(1,1) and (3,-8) -8-1/3-1=-9/2 m=-9/2 ,y=-9/2x+b
1=-9/2(1)+b b=11/2
y=-9/x+11/2
3.(2.-3) and (5,-2) m=1/3 ,y=1/3x+b
-3=1/3(2)+b -3=2/3+b
-3-2/3=b
b=-11/3
y=1/3x-11/3
4.(2,5)and (4,3) m=-1 y=-1x+b
5=-1(2)+b 5=-2+b
5+2=b
b=7
y=-1x+7
6.(-3,-5) and (-1,-3) m=2/2=1 y=1x+b
-5=1(-3)+b -5=-3+b
-5+3=b
-2=b
y=1x-2
Step-by-step explanation: