Answer:
B) 0.59 M NaCl.
Explanation:
- It is known that the no. of millimoles of NaCl before dilution = the no. of millimoles of NaCl after dilution.
∵ (MV) before dilution = (MV) after dilution.
<em>∴ M after dilution = (MV) before dilution / V after dilution </em>= (3.2 M)(25.0 mL)/(135.0 mL) = <em>0.5926 M ≅ 0.59 M.</em>
Answer: 
Explanation:
First we have to calculate the heat absorbed by bomb calorimeter
Formula used :

= heat absorbed by calorimeter = ?
= specific heat of = 10.69 kJ/K
= final temperature = 
= initial temperature = 

As heat absorbed by calorimeter is equal to the heat released by acetylene during combustion.
Thus 1.53 gram of acetylene releases heat of combustion = 258.7kJ
So, 26.04 g/mole of acetylene releases heat of combustion 
Therefore, the heat of combustion of acetylene is, 
Answer:
B
Explanation:
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Answer:
the answer would be 6.720
Simply subtract the combined mass by the mass of the beaker.
The answer has 3 decimal places because the least amount of decimal places in the equation is 3.