Answer:
the sample has mass of 50mg initially
Explanation:
https://youtu.be/ietdukGMG5c
Answer:
One of each
Explanation:
Be is in Group 2, so it loses its two valence electrons in a reaction to form Be²⁺ ions.
Carbonate ion has the formula CO₃²⁻.
We can use the criss-cross method to work out the formula of beryllium carbonate.
The steps are
Write the symbols of the anion and cation.
Criss-cross the numbers of the charges to become the subscripts of the other ion.
Write the formula with the new subscripts.
Divide the subscripts by their highest common factor.
Omit all subscripts that are 1.
When you use this method with Be²⁺ and CO₃²⁻, you might be tempted to write the formula for the beryllium carbonate as Be₂(CO₃)₂
However, you can divide the subscripts by their largest common factor (2).
This gives you the formula Be₁(CO₃)₁.
We omit subscripts that are 1, so the correct formula is
BeCO₃
There is one Be²⁺ ion and one CO₃²⁻ ion in a formula unit of beryllium carbonate.
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Answer: -
1.34 L
Explanation: -
Initial Pressure P 1 = 39.1 bar
Initial Temperature T 1 = 643 K
Let the initial volume be V 1.
Final pressure P 2 = 87.0 bar
Final temperature T 2 = 525 K.
Final volume V 2 = 0.492 L
Using the equation


Plugging in the values
We have
V 1 = 87 bar x 0.492 L x 643 K / (39.1 bar x 525 K)
= 1.34 L
Thus, a gas is contained in a thick-walled balloon. When the pressure changes from 39.1 bar to 87.0 bar the volume changes from 1.34 L to 0.492L and the temperature changes from 643K to 525K
covalent bond is firmed between two atoms