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svet-max [94.6K]
3 years ago
10

A set of aqueous solutions are prepared containing different acids at the same concentration: acetic acid, chloric acid and hydr

obromic acid. Which solution(s) are the most electrically conductive?
Chemistry
1 answer:
navik [9.2K]3 years ago
3 0

Answer:

The solutions of hydrobromic acid and of chloric acid are the most electrically conductive.

Explanation:

The electrical conductivity of a solution is determined by the concentration of ions in the solution. The acids listed react with water to form ions. In the case of hydrobromic acid, for example, the reaction is as follows:

HBr + H2O >> H3O(+) + Br(-)

Hydrobromic acid and chloric acid are strong acids, meaning the reaction is considered to proceed at 100%. Acetic acid, however, is a weak acid and the reaction with water does not go to completion, so there are less ionic species in the solution of acetic acid, which makes it less electrically conductive.

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3 years ago
What is the concentration of a solution formed by diluting 25.0 ml of a 3.2 M NaCl solution to 135.0 ml?
Irina-Kira [14]

Answer:

B) 0.59 M NaCl.

Explanation:

  • It is known that the no. of millimoles of NaCl before dilution = the no. of millimoles of NaCl after dilution.

∵ (MV) before dilution = (MV) after dilution.

<em>∴ M after dilution = (MV) before dilution / V after dilution </em>= (3.2 M)(25.0 mL)/(135.0 mL) = <em>0.5926 M ≅ 0.59 M.</em>

4 0
3 years ago
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Oxyacetylene torches produce such high temperature that they are often used to weld and cut metal. When 1.53 g of acetylene (C2H
hodyreva [135]

Answer: 4403kJ/mole

Explanation:

First we have to calculate the heat absorbed by bomb calorimeter  

Formula used :

q_b=c_b\times (T_{final}-T_{initial})

q_b = heat absorbed by calorimeter = ?

c_b = specific heat of = 10.69 kJ/K

T_{final} = final temperature = 44.688^oC=(273+44.688)K=317.688K

T_{initial} = initial temperature = 20.486^oC=(273+20.486)K=293.486K

q_b=10.69kJ/K\times (317.688-293.486)=258.7kJ

As heat absorbed by calorimeter is equal to the heat released by acetylene during combustion.

Thus 1.53 gram of acetylene releases heat of combustion = 258.7kJ

So, 26.04 g/mole of acetylene releases heat of combustion \frac{258.7}{1.53}\times 26.04=4403kJ/mole

Therefore, the heat of combustion of acetylene is, 4403kJ/mole

7 0
4 years ago
Which is an example of kinetic energy?
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Answer:

B

Explanation:

I'm not sure.,jsjajjwkwkpasbxbaakjwiw

4 0
3 years ago
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PLZ HELP!!!! NO LINKS<br>​
Svetradugi [14.3K]

Answer:

the answer would be 6.720

Simply subtract the combined mass by the mass of the beaker.

The answer has 3 decimal places because the least amount of decimal places in the equation is 3.

4 0
3 years ago
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