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Sauron [17]
4 years ago
13

D)(-1) • (-1) •(-1).​

Chemistry
1 answer:
Tom [10]4 years ago
8 0

Answer:

D

Explanation:

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Which of the following is the balanced equation for P + O2 → P2O5? Question 3 options: A) 4P + O2 → 2P2O B) P + 5O2 → 2P2O5 C) 4
Luden [163]

Given equation:

P + O2 → P2O5

In order for the equation to be balanced, the stoichiometry of the atoms of one kind on the reactant side must be equal to that on the product

Reactants                                            Products

P = 1                                                       P = 2

O = 2                                                     O = 5

The balanced equation would be:

4P + 5O2 → 2P2O5

Reactants                                            Products

P = 4                                                      P = 4

O = 10                                                    O = 10

Ans: D)


4 0
4 years ago
Read 2 more answers
If a solution conducts electricity, it is positive evidence that
BlackZzzverrR [31]

Answer:

If a solution conducts electricity, it is positive evidence that solute dissolved in solvent is electrolyte.

3 0
3 years ago
How many grams are in 3.5 moles of H2O?
Lerok [7]

Answer:

Hi

Explanation:

We assume you are converting between moles H2O and gram. You can view more details on each measurement unit: molecular weight of H2O or grams This compound is also known as Water or Dihydrogen Monoxide. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles H2O, or 18.01528 grams.

3 0
3 years ago
2 H2S(g) ⇄ 2 H2(g) + S2(g) Kc = 9.3× 10-8 at 400ºC 0.47 moles of H2S are placed in a 3.0 L container and the system is allowed t
Anon25 [30]

<u>Answer:</u> The concentration of hydrogen gas at equilibrium is 1.648\times 10^{-3}M

<u>Explanation:</u>

We are given:

Initial moles of hydrogen sulfide gas = 0.47 moles

Volume of the container = 3.0 L

The molarity of solution is calculated by using the equation:

\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of the solution}}

So, \text{Initial molarity of hydrogen sulfide gas}=\frac{0.47}{3}=0.1567M

The given chemical equation follows:

                          2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)

<u>Initial:</u>                  0.1567

<u>At eqllm:</u>           0.1567-2x       2x         x

The expression of K_c for above equation follows:

K_c=\frac{[H_2]^2[S_2]}{[H_2S]^2}

We are given:

K_c=9.3\times 10^{-8}

Putting values in above equation, we get:

9.3\times 10^{-8}=\frac{(2x)^2\times x}{(0.1567-2x)^2}\\\\x=8.24\times 10^{-4}

So, equilibrium concentration of hydrogen gas = 2x=(2\times 8.24\times 10^{-4})=1.648\times 10^{-3}M

Hence, the concentration of hydrogen gas at equilibrium is 1.648\times 10^{-3}M

7 0
3 years ago
In the reaction 2H2O (l) + 2Cl– (aq) → H2 (g) + Cl2 (g) + 2OH– (aq), which substance is reduced?
Leno4ka [110]

A. H2O is the substance reduced.

H2O + 2e^(-) →H_2 + 2OH^(-)

The substance that gains electrons is reduced.  

Remember OIL <em>RIG </em>(<em>R</em>eduction <em>I</em>s <em>G</em>ain of electrons) and

LEO the lion says <em>GER</em> (<em>G</em>ain of <em>E</em>lectrons is <em>R</em>eduction).

5 0
3 years ago
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