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mash [69]
3 years ago
10

Which linear equations have an infinite number of solutions? Check all that apply. (x – ) = (x – left-parenthesis x minus StartF

raction 3 Over 7 EndFraction right-parenthesis equals StartFraction 2 Over 3 EndFraction left-parenthesis StartFraction 3 Over 2 x EndFraction minus StartFraction 9 Over 14 EndFraction right-parenthesis.) 8(x + 2) = 5x – 14 12.3x – 18 = 3(–6 + 4.1x) (6x + 10) = 7(StartFraction one-half EndFraction left parenthesis 6 x plus 10 right-parenthesis equals 7 left-parenthesis StartFraction 3 Over 7 x minus 2 right-parenthesis.x – 2) 4.2x – 3.5 = 2.1 (5x + 8)
Mathematics
2 answers:
allochka39001 [22]3 years ago
4 0

Answer:

a, (x-3/7)=2/3(3/2x-9/14), and c, 12.3x – 18 = 3(–6 + 4.1x).

Step-by-step explanation:

i just answered that question

suter [353]3 years ago
3 0

Answer:

its A and C

Step-by-step explanation:

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If an organism had 200 atoms of carbon-14 at death, how many atoms will be present after 14,325 years? Round the answer to the n
Lilit [14]

Answer:

35.34 atoms will be present after 14,325 years.

Step-by-step explanation:

Given : Carbon-14 has a half-life of approximately 5,730 years. This exponential decay can be modeled with the function N(t) = N0. If an organism had 200 atoms of carbon-14 at death.

To find : How many atoms will be present after 14,325 years?

Solution :

The half-life exponential function modeled is N=N_o(\frac{1}{2})^{\frac{t}{h}}

Where, N_o=200 is the initial atoms

N is the total number of atoms.

t=14,325 years is the time  

h=5,730 years is the half-life time

Substitute the value in the formula,

N=200(\frac{1}{2})^{\frac{14325}{5730}}

N=200(\frac{1}{2})^{2.5}

N=200(0.1767)

N=35.34

Therefore, 35.34 atoms will be present after 14,325 years.

3 0
3 years ago
PLS HELP ASAP !!! WILL MARK BRAINLIEST !!
Olenka [21]
I believe the answer is A
4 0
3 years ago
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What is the cost of a 12-in. by 12-in. book with 28 pages?
Sloan [31]
It depends if it is hard back or a soft back
6 0
3 years ago
What is the Pemdas answer for 5-0×3+9÷3
padilas [110]
PEMDAS
since we don't have exponentes or paretnahsees we do
muliplictaion or division whichever comes first (since division is just multiplication of a fraction)

addition or subtraction whichever comes first (since subtraction is adding a negative)

so
multiply/divide
0 times 3=0
9/3=3

now we have
5-0+3
add/subtract
5-0=5
5+3=8
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6 0
3 years ago
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3 1/2 X 1 2/3 =<br> what is it?????
puteri [66]

Answer:

5 \frac{5}{6}

Step-by-step explanation:

3 \frac{1}{2}  \times 1  \frac{2}{3}  \\  = 5 \ \frac{5}{6}

6 0
3 years ago
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