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mash [69]
3 years ago
10

Which linear equations have an infinite number of solutions? Check all that apply. (x – ) = (x – left-parenthesis x minus StartF

raction 3 Over 7 EndFraction right-parenthesis equals StartFraction 2 Over 3 EndFraction left-parenthesis StartFraction 3 Over 2 x EndFraction minus StartFraction 9 Over 14 EndFraction right-parenthesis.) 8(x + 2) = 5x – 14 12.3x – 18 = 3(–6 + 4.1x) (6x + 10) = 7(StartFraction one-half EndFraction left parenthesis 6 x plus 10 right-parenthesis equals 7 left-parenthesis StartFraction 3 Over 7 x minus 2 right-parenthesis.x – 2) 4.2x – 3.5 = 2.1 (5x + 8)
Mathematics
2 answers:
allochka39001 [22]3 years ago
4 0

Answer:

a, (x-3/7)=2/3(3/2x-9/14), and c, 12.3x – 18 = 3(–6 + 4.1x).

Step-by-step explanation:

i just answered that question

suter [353]3 years ago
3 0

Answer:

its A and C

Step-by-step explanation:

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Step-by-step explanation:

We have xy = 28, x² + y² = 65 and x³ + y³ = 407.

Since (x + y)(x² - xy + y²) = x³ + y³,

x + y = (x³ + y³)/(x² + y² - xy)

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3 years ago
A fair coin is flipped twelve times. What is the probability of the coin landing tails up exactly nine times?
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Answer:

P\left(E\right)=\frac{55}{1024}

Step-by-step explanation:

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We can determine the number of ways that such a sequence could contain exactly 9 tails is the number of ways of choosing 9 out of 12, using the formula

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Plug in n = 12 and r = 9

       =\frac{12!}{9!\left(12-9\right)!}

       =\frac{12!}{9!\cdot \:3!}

       =\frac{12\cdot \:11\cdot \:10}{3!}            ∵ \frac{12!}{9!}=12\cdot \:11\cdot \:10

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Thus, the probability will be:

P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}

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Thus, the probability of the coin landing tails up exactly nine times will be:

P\left(E\right)=\frac{55}{1024}

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