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dmitriy555 [2]
3 years ago
6

Solve to following equation for x: 6(4x +5) = 3(x + 8) +3

Mathematics
1 answer:
ioda3 years ago
7 0
The answer to all your problems is x=-1/7.
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Write an equation, and express the product in standard form.
rosijanka [135]

Answer: 3 copies of 5 tenths = 3*0.5 = 1.5

Step-by-step explanation:

Ok, if we have:

"3 copies of a number B"

This is written as:

3*B

And we have that the number B is "5 tenths"

Now, a tenth is the first digit after the decimal point.

Then 5 tenths = 5*0.1 = 0.5

B = 0.5

3 copies of 5 tenths = 3*0.5 = 1.5

7 0
3 years ago
What is the equation for the line that passes through the point (0,0) and has a slope of -1/2
prisoha [69]
Assuming it's a linear equation, y= -1/2x

6 0
3 years ago
What is the actual distance of 9 cm on a map whose scale shows that 3 cm = 5 km? A. 18 km incorrect answer B. 12 km incorrect an
soldier1979 [14.2K]

Answer:

15 km

Step-by-step explanation:

3 cm on the map = 5 km

3 x 3 = 9 cm

5 x 3 = 15 km

So, 9 cm on the map = 15 km

4 0
3 years ago
Read 2 more answers
Compared to a model of 9/12 , a model of 3/4 will show -------------(A)3 Times as many B)1/3 times as many D)The same number of)
aleksandrvk [35]

9514 1404 393

Answer:

  B, B

Step-by-step explanation:

A model of 9/12 will have 12 parts, 9 of which are shaded.

A model of 3/4 will have 4 parts (1/3 as many), 3 of which are shaded. Each part of this model will correspond to 3 parts of the 9/12 model. Hence, each part is 3 times the size of a part in the 9/12 model.

  B) 1/3 times as many

  B) 3 times the size

4 0
3 years ago
1 Solve the compound inequality 4x&gt;-16 or 6x &lt;-48<br>​
Yuliya22 [10]

Answer:

Step-by-step explanation:

4x > -16 reduces to x > -4:  All numbers greater than x = -4 (shaded area to the right of -4).

6x < -48 reduces to x < -8:  All numbers to the left of -8 (shaded area to the left of -8).

Solution:  (-infinity, -4) ∪ (-8, infinity)

The number line between -8 and -4 is not part of the solution set (is not shaded or darkened)

Draw an open circle at -8 and extend an arrow to the left of this circle.  Then draw an open circle at -4 and extend an arrow to the right of this circle.

5 0
3 years ago
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