Solve to following equation for x: 6(4x +5) = 3(x + 8) +3

One watering system needs about three times as long to complete a job as another warning system when both systems operate at the

algol13

Answer:

One watering system requires 36 minutes to complete the job alone while another watering system requires 12 minutes to complete the job alone.

Step-by-step explanation:

Given:

Both the system can complete the job = 9 minutes

We need find the time required by each system to do the job.

Solution:

Let the time required by another watering system to complete the job be 'x' mins.

Now given:

One watering system needs about three times as long to complete a job as another watering system.

Time required by one watering system = $3x$

Rate to complete the job by another watering system = $\frac{1}{x}\ job/min$

Rate to complete the job by One watering system = $\frac{1}{3x}\ job/min$

Rate at which both can complete the job = $\frac{1}{9}\ job/min$

So we can say that;

Rate at which both can complete the job is equal to sum of Rate to complete the job by another watering system and Rate to complete the job by One watering system.

framing in equation form we get;

$\frac{1}{x}+\frac{1}{3x}=\frac19$

Now taking LCM to make the denominator common we get;

$\frac{1\times3}{x\times 3}+\frac{1\times1}{3x\times1}=\frac19\\\\\frac{3}{3x}+\frac{1}{3x}=\frac19\\\\\frac{3+1}{3x}=\frac{1}{9}\\\\\frac{4}{3x}=\frac{1}{9}$

By Cross multiplication we get;

$4\times9 =3x\\\\3x =36$

Dividing both side by 3 we get;

$\frac{3x}{3}=\frac{36}{3}\\\\x=12\ min$

Time required by One watering system = $3x =3\times 12 =36\ min$

Hence One watering system requires 36 minutes to complete the job alone while another watering system requires 12 minutes to complete the job alone.

6 0

3 years ago

P=2L +2W;P=32,W=7 25 16 12.5 9

Marianna [84]

Answer:

L = 9

Step-by-step explanation:

Assuming you are trying to find L

P = 2L + 2W

P = 32

32 = 2L + 2W

W = 7

32 = 2L + (2 × 7)

32 = 2L + 14

2L = 32 - 14

2L = 18

L = 9

5 0

3 years ago

Suppose cos(π/2−x) =3/5, cos x =4/5 find sin, tan, csc, sec, cot

Pani-rosa [81]

Cos (π/2 - x) = sin x = 3/5
tan x = sin x / cos x = 3/5 / 4/5 = 3/4
csc x = 1/sin x = 1 / 3/5 = 5/3
sec x = 1/cos x = 1 / 4/5 = 5/4
cot x = 1/tan x = 1 / 3/4 = 4/3.

5 0

3 years ago

PLEASE PLEASE I SUCK AT MATH AND ITS ALL DUE FRIDAY PLEASE 10 piont !!! Select all the correct systems of equations.

alekssr [168]

Answer:

2x + y = 17

-6x = 3y - 51

Step-by-step explanation:

You get an infinite number of solutions when two equations are really just the same. This means you can convert one into the other simply by multiplying one to get the other.

In the above answer, if you multiply the above by -3 you get:

-6x -3y = -51

which is of course -6x = 3y - 51

So that is an example of a pair that has infinite solutions.

To find all of them, you'd carefully have to compare each 2 and see if there is a multiplier to convert one into the other. You can do that!

4 0

2 years ago

How do you do rate of change?

ahrayia [7]

Answer:

Y2-y1/x2-x1

Step-by-step explanation:

The rate of change is the same thing as slope. So you would do the same thing as you would for slope.

Ex. you have two coordinate points. (4,4) (5,9)

y2 would be 9

y1 would be 4

x2 would be 5

x1 would be 4

so you would do 9-4=5

then 5-4=1

So your rate of change/slope would be 5/1 or 5

7 0

2 years ago