Answer:
V1 = 60 km/h
V2 = 40 Km/h
Step-by-step explanation:
The speed of an object is defined as
Speed = distance / time
Let
V1 be the speed of the faster car
V2 be the speed of the other car
t1 the time it took for the first car to arrive
t2 the time it took for the second car to arrive
d1 the distance traveled by first car
d2 the distance traveled by second car
We know thanks to the problem that
V1 = V2 + 20 Km/h
t1 = t2 - 1 hour
d1 = d2 = 120 Km
d1 = V1 * t1
d2 = V2* t2
V1 * t1 = V2* t2
V1* t1 = (V1 -20)*(t1 +1)
The system of equations
(V1 -20)*(t1 +1) = 120
V1 * t1 = 120
120 + (120/t1) -20*t1 = 140
(120/t1) -20*t1 = 20
Which gives,
t1 = 2
This means
V1 = 60 km/h
V2 = V1 - 20 Km/h = 40 Km/h
The answer is 4. The question is what is 2+2?
base is a square 16m 6m
Step-by-step explanation:
A square is a regular quadrilateral and it has four equal sides and four equal angles (90 degree angle or right angles).
A square quadrilateral with vertices ABCD would be denoted by ABCD. The perimeter of a square (quadrilateral) is given by:
P = 4a
Where a is the length of each side.
Perimeter of the square:
P = 4a
P = 4 × 16 cm
P = 64 cm
Hence, the perimeter of square is 64 cm.
1+3+5+7+...+999 =
= 1+2+3+4+...+500
+1+2+3+...+499
= 2·(1+2+3+...+499) + 500
= 2·(499·500)/2 + 500
= 499·500 + 500
= 500·(499 + 1)
= 500·500
= 250.000
Answer:
6,889
<em>Multiply </em>83 x 83.
<h3>
83 x 83 = 6,889.</h3>
Therefore, 83 squared is 6,889.
