Answer:
The second one from the top
Step-by-step explanation:
x^(5/3) y^1/3)
First you would distribute the 3. So it would be (3x+6)+14+7x. Since you can’t do anything inside the parentheses, you drop them. Then you’d combine like terms. 3x+7x is 10x, and 14+6 is 20. That would get you your answer, 10x+20
The best thing to do for this question is to find a common denominator, and the best way to do this is to list all of the multiples and find the smallest common one.
8- 8, 16, 24, 32, 40, 48
20- 20, 40, 60
In this, 40 is the lowest, so you have to multiply 5/8 by 5 at the top and bottom, and this gives you 25/40. You have to multiply the second fraction by 2, and this becomes 22/40.
Therefore, the larger fraction is 5/8.
The alternative method is to turn them into decimals and compare them this way. 5/8= 0.625 & 11/20= 0.55
Hope this helps
To calculate the distance between two points on the coordinate system you have to use the following formula:
![d=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%5B%5D%7B%28x_1-x_2%29%5E2%2B%28y_1-y_2%29%5E2%7D)
Where
d represents the distance between both points.
(x₁,y₁) are the coordinates of one of the points.
(x₂,y₂) are the coordinates of the second point.
To determine the length of CD, the first step is to determine the coordinates of both endpoints from the graph
C(2,-1)
D(-1,-2)
Replace the coordinates on the formula using C(2,-1) as (x₁,y₁) and D(-1,-2) as (x₂,y₂)
![\begin{gathered} d_{CD}=\sqrt[]{(2-(-1))^2+((-1)-(-2))}^2 \\ d_{CD}=\sqrt[]{(2+1)^2+(-1+2)^2} \\ d_{CD}=\sqrt[]{3^2+1^2} \\ d_{CD}=\sqrt[]{9+1} \\ d_{CD}=\sqrt[]{10} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20d_%7BCD%7D%3D%5Csqrt%5B%5D%7B%282-%28-1%29%29%5E2%2B%28%28-1%29-%28-2%29%29%7D%5E2%20%5C%5C%20d_%7BCD%7D%3D%5Csqrt%5B%5D%7B%282%2B1%29%5E2%2B%28-1%2B2%29%5E2%7D%20%5C%5C%20d_%7BCD%7D%3D%5Csqrt%5B%5D%7B3%5E2%2B1%5E2%7D%20%5C%5C%20d_%7BCD%7D%3D%5Csqrt%5B%5D%7B9%2B1%7D%20%5C%5C%20d_%7BCD%7D%3D%5Csqrt%5B%5D%7B10%7D%20%5Cend%7Bgathered%7D)
The length of CD is √10 units ≈ 3.16 units
6x - 5y = 17
7x + 3y = 11
to eliminate x....there is a couple ways to do this...
u can multiply equation 1 by 7 and equation 2 by -6
or
u can multiply equation 1 by -7 and equation 2 by 6
