Answer:
The correct options are: Interquartile ranges are not significantly impacted by outliers. Lower and upper quartiles are needed to find the interquartile range. The data values should be listed in order before trying to find the interquartile range. The option Subtract the lowest and highest values to find the interquartile range is incorrect because the difference between lowest and highest values will give us range. The option A small interquartile range means the data is spread far away from the median is incorrect because a small interquartile means data is nor spread far away from the median
btw my name is not Google, but I'll post anyhow.
if all three friends only have 5lbs of flour only and therefore only 19 cups of flour, well, each batch takes up 2 cups of flour and they only have 19 cups, 19/2 gives us 9 with a remainder of 1.
so 9 whole batches.
8x3+5=(—x3)+(—x5)
24+40 =(8x3)+(8x5)
64=24+40
64=64
The expected duration of the activity is 29 days and 4 hours.
Step-by-step explanation:
Step 1:
The optimistic time, 
= 25 days,
The most likely estimate, 
= 29 days.
The pessimistic time, 
= 34 days.
According to PERT, the expected duration of the activity, 
Step 2:
By substituting the given values, we get
0.1666 days = 
29.1666 days approximately equal 29 days and 4 hours.
Answer:
I think the answer is the last choice
