Answer:
1492.88
Step-by-step explanation:
V = πr^2 h/3
3.14 × 18^2
3.14 × 324 = 1017.36
1017.36 × 4.4 = 4476.384
4476.384 ÷ 3 = 1492.88
Hope this helped.
The equation of the line will be (assuming the y-intercept equal to zero):
y = 2.5*x
<h3>
What is Tahila's mistake?</h3>
We know that we have a linear equation of the form:
y = a*x + b
Such that we know that the line passes through (-3, -7.5), notice that the proposed equation is:
y = 0.5*x
If you evaluate that in -3, you get:
y = 0.5*-3 = -1.5
So this line does not pass through (-3, -7.5).
If we assume that b = 0 in the linear equation, then we can find the value of a as:
-7.5 = a*-3
a = 7.5/3 = 2.5
Then the linear equation is:
y = 2.5*x
If you want to learn more about linear equations:
brainly.com/question/1884491
#SPJ1
Answer:
r = 144 units
Step-by-step explanation:
The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.
Substituting the terms of the equation and the derivative of r´, as follows,

Doing the operations inside of the brackets the derivatives are:
1 ) 
2) 
Entering these values of the integral is

It is possible to factorize the quadratic function and the integral can reduced as,

Thus, evaluate from 0 to 16
The value is 
5 * 23 is equal to 115. =)