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ryzh [129]
3 years ago
14

3 bags of chips cost 14.70 what is the price per bag

Mathematics
2 answers:
Iteru [2.4K]3 years ago
8 0

Answer:

4.90

Step-by-step explanation:

14.70 times 1 which is 14.70

then divide 14.70 by 3

which gives you 4.90

yawa3891 [41]3 years ago
7 0

Answer:

4.90

Step-by-step explanation:

p/a=x

price/amount=x

14.70/3=4.90

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I need some help with math.<br> Who can help me?
Evgesh-ka [11]

Step-by-step explanation:

10^2 = 100

10^-2 = 1/100 ➡ 0.01

5 0
3 years ago
What is 4/20 simplified
frozen [14]
4/20 simplified would be 1/5. You must know what simplify means first. It means to break down a fraction to its simplest form. So, to simplify 4/20, you must divide 4 from the denominator and numerator. A numerator is a number that is the number above the line. A denominator is the number on the bottom of the line. 
Dividing 4 from the denominator and numerator would make it 1/5. Therefore, the answer in simplest form is 1/5. Good luck!
6 0
3 years ago
Read 2 more answers
What is the equation of the line that passes through the point (-5,2) and has a slope of 4/5
dedylja [7]

Answer:

4x - 5y + 30 = 0

Step-by-step explanation:

When a slope of a line and a point passing through it is given then we use slope - one point form to determine the equation of the line.

It is given by:

                      $ (y - y_1) = m (x - x_1) $

where $m$ is the slope of the line and

           $ (x_1, y_1) $ is the point passing through it.

Here $m = \frac{4}{5} $ and $ (x_1 , y_1) = (-5,2) $.

Substituting in the equation we get

$ (y - 2) = \frac{4}{5} (x + 5) $

$ \implies 5y - 10 = 4x + 20 $

$ \implies 4x - 5y + 30 = 0 $

5 0
3 years ago
In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.
konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

BC^2=BD\cdot AB.

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.

Take positive value x. You get

AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.

2. According to the previous theorem,

AC^2=AD\cdot AB.

Then

AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

Answer: AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D

This means that you cannot find solutions of this equation. Then CD≠2 cm.

8 0
4 years ago
Read 2 more answers
Which of the following represents a function?
zhuklara [117]
The fourth one since it will pass the vertical test.
3 0
3 years ago
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