Find the total of the figure below. PLEASEEE HELPPPPPPPP!

Mathematics

1 answer:

KATRIN_1 [288]4 years ago

3 0

The answer is 134 ft^2

the area of the smaller rectangle:
$5 \times 6 = 30$

the area of the other rectangle:
$8 \times 13 = 104$

the area of the whole shape:
$104 +30 = 134$

good luck

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Consider the quadratic equation. x^2=4x-5. How many solutions does the equation have?

Vesna [10]

x^2=4x-5
subtract 4x from both sides
x^2-4x=-5
add 5 to both sides
x^2-4x+5=0

input into quadratic formula which is x= $\frac{-b+ \sqrt{b^2-4ac} }{2a}$ or $\frac{-b- \sqrt{b^2-4ac} }{2a}$

si ax^2+bx+c
so a=1
b=-4
c=5
input
$\frac{-(-4)+ \sqrt{-4^2-4(1)(5)} }{2(1)}$ = $\frac{4+ \sqrt{16-20} }{2(1)}$ = $\frac{4+ \sqrt{-4} }{2}$ = $\frac{4+ \sqrt{4} times \sqrt{-1} }{2}$ $\frac{4+2 times \sqrt{-1} }{2}= \frac{6 times \sqrt{-1} }{2}=3 times \sqrt{-1} [\tex][\tex]\sqrt{-1}$ representeds by 'i' so solution is 3i

then if other way around then wyou would do
$\frac{-(-4)- \sqrt{-4^2-4(1)(5)} }{2(1)}$ = $\frac{4- \sqrt{16-20} }{2(1)}= \frac{4- \sqrt{-4} }{2} =\frac{4- \sqrt{4} times \sqrt{-1} }{2}= \frac{4-2 times \sqrt{-1} }{2}=\frac{2 \sqrt{-1} }{2}= \sqrt{-1}$ and [\tex]\sqrt{-1} [/tex] is represented by i

the solution is x=3i or i (i= $\sqrt{-1}$ )
but i is not real, it is imaginary so there are no real solution so the answer is C

3 0

4 years ago

Solve. −0.65p − 4 = 0.35p The solution is p =

Nuetrik [128]

Answer:

Step-by-step explanation:

Solution,

p=-4

If you found my answer useful then please mark me brainliest.

6 0

3 years ago

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