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Illusion [34]
3 years ago
13

Find the total of the figure below. PLEASEEE HELPPPPPPPP!

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
3 0
The answer is 134 ft^2



the area of the smaller rectangle:
5 \times 6 = 30



the area of the other rectangle:
8 \times 13 = 104




the area of the whole shape:
104 +30 = 134



good luck
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What is the solution
gladu [14]

Answer:

  1. 3x-1/4=-5/11
  2. 11 (3x-1)=4 (5)
  3. 33x-11=20
  4. 33x=20+11
  5. 33x=31
  6. x=31/33
  7. x=?
8 0
2 years ago
A box is being created out of a 15 inch by 10 inch sheet of metal. Equal-sized squares are cutout of the corners, then the sides
ivolga24 [154]

Answer:

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box  has largest volume.

Step-by-step explanation:

Given that,

A box is being created out of a 15 inches by 10 inches sheet of metal.

The length of the one side of the squares which are cut out of the each corners of the metal sheet be x.

The length of the metal box be = (15-2x) inches.

The width of the metal box be =(10-2x) inches

The height of the metal box be =x inches

Then, the volume of the metal box= length×width×height

                                                         =(15-2x)(10-2x)x cubic inches

                                                         =(150x-50x²+4x³) cubic inches

∴ V= 4x³-50x²+15x

Differentiating with respect to x

V'=12x²-100x+15

Again differentiating with respect to x

V''=24x-100

For maximum or minimum value, V'=0

12x²-100x+15=0

Apply quadratic formula x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}, here a=12, b= -100 and c=15

x=\frac{-(-100)\pm\sqrt{(-100)^2-4.12.15}}{2.12}

\Rightarrow x=\frac{100\pm\sqrt{9280}}{2.12}

\Rightarrow x=0.1528,8.18

For x= 8.18, The value of (15-2x) and (10-2x) will negative.

∴x=0.1528 .

Now, V''|_{x=0.1528}=24(0.1528)-100

∴At x=0.1528 inch, the volume of the metal box will be maximum.

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box  has largest volume.

4 0
3 years ago
What is the equation of the line
Sphinxa [80]

x = 0

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7 0
3 years ago
Read 2 more answers
Someone please help
AleksandrR [38]

Replace y with 31:

31 = 7x -4

Add 4 to both sides:

35 = 7x

Divide both sides by 7:

x = 5

Input x = 5

6 0
2 years ago
Find all points having an x-coordinate of 2 whose distance from the point (-1,-2) is 5
mariarad [96]
The\ equation\ of\ the\ circle:(x-a)^2+(y-b)^2=r^2\\\\where\ (a;\ b)\ -the\ coordinates\ of\ the\ center;\ r-the\ radius\\-----------------------------\\(-1;-2)-the\ center\ of\ the\ circle\\r=5\\\\The\ equation:(x+1)^2+(y+2)^2=5^5\\\\Put\ x=2\ to\ the\ equation:\\\\(2+1)^2+(y+2)^2=25\\3^2+(y+2)^2=25\\9+(y+2)^2=25\\(y+2)^2=25-9\\(y+2)^2=16\iff y+1=\pm\sqrt{16}\\\\y+1=-4\ or\ y+1=4\ \ \ \ \ |subtract\ 1\ from\ both \sides\\y=-5\ or\ y=3\\\\Answer:(2;-5)\ and\ (2;\ 3).
5 0
3 years ago
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