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stepan [7]
3 years ago
11

Hiroshi paid $34.95 to rent a car for a day, plus 12¢ for each kilometre he drove. The total rental cost, before taxes, was $55.

11. How far did Hiroshi drive that day?
Mathematics
1 answer:
Butoxors [25]3 years ago
7 0

Answer:

Step-by-step explanation:

if the total cost was 55.11 we will do:

55.11-34.95=20.16

20.16/.12=168

Hiroshi drove 168 km that day

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abruzzese [7]
The points of the graph are> (1,1), (2,2), (3,4), (4,8).

Then the sequence is:

- for the x-coordinate: 1, 2, 3, 4, 5, 6, 7, ...

- for the y-coordinate: 1, 2, 4, 8, which is: 2^0, 2^1, 2^2, 2^ 3, ... so the next y-coordinates are 16, 32, 64, 128, ...

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(If A+B+C=180) <br>tan 2A + tan 2B + tan 2C = tan 2A tan 2B tan 2C​
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Step-by-step explanation:

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3 years ago
Haley works at a candy store. There are 10 types of bulk candy. Find the probability that one type of candy will be chosen more
DIA [1.3K]

Answer:

Probability that one type of candy will be chosen more than once in 10 trials = 0.2639

Step-by-step explanation:

This is a binomial experiment because

- A binomial experiment is one in which the probability of success doesn't change with every run or number of trials.

- It usually consists of a number of runs/trials with only two possible outcomes, a success or a failure. (10 trials, with the outcome of each trial being that we get the required candy or not)

- The outcome of each trial/run of a binomial experiment is independent of one another.

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = 10 trials

x = Number of successes required = number of times we want to pick a particular brand of candy = more than once, that is > 1

p = probability of success = probability of picking a particular brand of candy from a bulk with 10 different types of candies = (1/10) = 0.10

q = probability of failure = Probability of not picking our wanted candy = 1 - p = 1 - 0.1 = 0.90

P(X > 1) = 1 - P(X ≤ 1)

P(X ≤ 1) = P(X = 0) + P(X = 1)

P(X = 0) = ¹⁰C₀ (0.10)⁰ (0.90)¹⁰⁻⁰ = 0.3486784401

P(X = 1) = ¹⁰C₁ (0.10)¹ (0.90)¹⁰⁻¹ = 0.387420489

P(X ≤ 1) = 0.3486784401 + 0.387420489 = 0.7360989291

P(X > 1) = 1 - 0.7360989291 = 0.2639010709 = 0.2639

Hope this Helps!!!

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Answer:

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