31 and 33.................
There are nine possible combinations as follows: bb, bc, bt, cb, cc, ct, tb, tc, tt, each having a probability of 1/9. The four combinations with a cab exactly one time are: bc, cb, ct, tc. Therefore the probability that she'll use a cab exactly one time is: 4/9.
-7+3/6+6=-4/12= -1/4
y+3= -1/4(x+6)
y+3= -1/4x-3/2
y=-1/4x-9/2
Answer:
D)
Step-by-step explanation:
7x + 4 = 3x + 68
7x - 3x = 68 - 4
4x = 64
x = 64/4
x = 16
I Hope I've helped you.