The age of Blain is 23 years old
<h3><u>Solution:</u></h3>
Let the age of Blain be "a" and age of Jillian be "b"
Given that Blain is two years older than three times Jillians age
So we can frame a equation as:
age of blain = 2 + 3(age of Jillian)
a = 2 + 3b ----- eqn 1
Also given that Jillian is also 16 years younger than Blain
Age of Jillain = Age of Blain - 16
b = a - 16 ---- eqn 2
Substitute eqn 2 in eqn 1
a = 2 + 3(a - 16)
a = 2 + 3a - 48
a - 3a = -46
-2a = -46
a = 23
Thus the age of Blain is 23 years old
Answer:
12/54
Step-by-step explanation:
4x3=12
6x9=54
Answer:
it the second one
Step-by-step explanation:
b/c 18times it self 2in x-1 is just talking it a way bone
2nd answer.
any pts in the shaded region satisfies your simultaneous equation.
Answer:
f(d) = 2900 - 20d
Step-by-step explanation:
We start with 2,900 and each week 20 is deducted from the account.
f(d) = 2900 - 20d