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vagabundo [1.1K]
3 years ago
14

The diagram shows the repairs performed on 2 types of cars.

Mathematics
1 answer:
Mama L [17]3 years ago
6 0

Answer:

The median is the same for both car

types, but Bandits have the lower

mean.

Step-by-step explanation:

From the boxplot attached, the median value for both car types can be clearly seen to be the same as the vertical line in between the box of both plots lie at the same point.

As for the mean which is the average of a set of data we could deduce from the plot that, the roadster data has a larger span than the bandit data with a far greater third percentile value. Hence, mean or average data for roadster will be higher Than that if bandits.

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Gina has a jar of marbles that contains 7 blue marbles, 5 red marbles, and 8 green marbles. She randomly selects a marble, recor
BigorU [14]

The probability that Gina randomly selected two red marbles is 1/19

<u>Explanation:</u>

Total number of marbles = 7 + 5 + 8

                                          = 20

The probability of getting two red marbles in the fraction form is given as:

P(first red marble) = number of red marbles / total number of marbles

P(first red marble) = \frac{5}{20} = \frac{1}{4}

P(second red marble) = number of red marbles after 1 white marble is removed / total number of marbles after 1 red marble is removed.

P(first red marble) = \frac{4}{19}

P(two red marbles) = P(first) X P(second)

                              = \frac{1}{4} X \frac{4}{19}

                              = \frac{1}{19}

Therefore, the probability that Gina randomly selected two red marbles is 1/19

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3 years ago
A survey is conducted to find out whether people in metropolitan areas obtain their news from television (Event T), an newspaper
MrMuchimi

Answer:

e) P ( R' | T ) = 0.62857

f)  P ( T' | N ) = 0.32258

g)  P ( R' | N ) = 0.70968

h) P ( T' | N&R ) = 5/6

Step-by-step explanation:

Given:

- The probability of Television as news source P ( T ) = 0.7

- The probability of Newspaper as news source P ( N ) = 0.62

- The probability of Radio as news source P ( R ) = 0.46

- The probability of Television & Newspaper as news source P (T&N) = 0.42

- The probability of Television & Radio as news source P (T&R) = 0.26

- The probability of Radio & Newspaper as news source P (R&N) = 0.18

- The probability of all 3 as news source P ( T & R & N ) = 0.03

Find:

Given that TV is a news source, what is the probability that radio is not a news source?

Given that newspaper is a news source, what is the probability that TV is not a news source?

Given that newspaper is a news source, what is the probability that radio is not a news source?

Given that both newspaper and radio are news sources, what is the probability that TV is not a news source?

Solution:

- We will first compute the individual probability of each event occurring alone.

   P (Television is the only news source) = P(T) - P(T&R) - P(T&N) + P(T&N&R)

   P ( Only Television ) = P ( only T ) = 0.7 - 0.42 - 0.26 + 0.03 = 0.05

   P (Newspaper is the only news source) = P(N)-P(N&R)-P(T&N)+P(T&N&R)

   P ( Only Newspaper ) = P ( only N ) = 0.62 - 0.18 - 0.42 + 0.03 = 0.05

   P (Radio is the only news source) = P(R) - P(T&R) - P(N&R) + P(T&N&R)

   P ( Only Radio ) = P ( only R ) = 0.46 - 0.26 - 0.18 + 0.03 = 0.05

- Now for part e)

   We are asked for a conditional probability of the form as follows:

            P ( R' | T ) = P ( R' & T ) / P ( T )

   First compute the probability that next news source is not Radio provided it is already a source of TV.                              

            P ( R' & T ) =  P( only T ) + P ( only T & N ) = 0.05 + 0.42 - 0.03 = 0.44

Hence,

            P ( R' | T ) = 0.44 / 0.7

            P ( R' | T ) = 0.62857

- Now for part f)

   We are asked for a conditional probability of the form as follows:

            P ( T' | N ) = P ( T' & N ) / P ( N )

   First compute the probability that next news source is not TV provided it is already a source of Newspaper.                              

            P ( T' & N ) =  P( only N ) + P ( only R & N ) = 0.05 + 0.18 - 0.03 = 0.2

Hence,

           P ( T' | N ) = 0.2 / 0.62

           P ( T' | N ) = 0.32258

- Now for part g)

   We are asked for a conditional probability of the form as follows:

            P ( R' | N ) = P ( R' & N ) / P ( N )

   First compute the probability that next news source is not Radio provided it is already a source of Newspaper.                              

            P ( R' & N ) =  P( only N ) + P ( only T & N ) = 0.05 + 0.42 - 0.03 = 0.44

Hence,

            P ( R' | N ) = 0.44 / 0.62

            P ( R' | N ) = 0.70968

- Now for part h)

   We are asked for a conditional probability of the form as follows:

            P ( T' | N&R ) = P ( T' & N & R) / P ( N & R )

   First compute the probability that next news source is not TV provided it is already a source of both radio and Newspaper.                              

            P ( T' & N & R) = P ( only N & R ) = 0.18 - 0.03 = 0.15

Hence,

            P ( T' | N&R ) = 0.15 / 0.18

            P ( T' | N&R ) = 5/6

6 0
3 years ago
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