The center and a point on a circle are given. Find the circumference to the nearest tenth.
1 answer:
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Answer:
The point C is 12.68 km away from the point A on a bearing of S23.23°W.
Step-by-step explanation:
Given that AB is 50 km and BC is 40 km as shown in the figure.
From the figure, the length of x-component of AC = |AB sin 80° - BC cos 20°|
=|50 sin 80° - 40 cos 20°|=11.65 km
The length of y-component of AC = |AB cos 80° - BC sin 20°|
=|50 cos 80° - 40 sin 20°|= 5 km
tan= 5/11.65
=23.23°
AC= km
Hence, the point C is 12.68 km away from the point A on a bearing of S23.23°W.
Answer:
294.5 m²
Step-by-step explanation:
shaded region = area of major sector + area of triangle
central angle of major sector = 360° - 130° = 230°
area of sector = area of circle × fraction of circle
A = π × 11.1² ×
= ≈ 247.3 m²
area of triangle = 0.5 × 11.1 × 11.1 × sin130° ≈ 47.2 m²
shaded area = 247.3 + 47.2 ≈ 294.5 m²