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jonny [76]
3 years ago
5

Can you help? What do you think ??

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
8 0

Answer:

The amount of money one may spend in a month may be greater than that of ones monthly payment especially when the payment is at a lower rate.

You might be interested in
Law of cosine find m<B a=11 b=12 c=17
Andrei [34K]
Cos (B) = (a^2 + c^2 -b^2) / (2 * a * c)
cos (B) = (11^2 +17^2 -12^2) / (2 * 11 * 17)
cos (B) = (121 + 289 -144) / (374)
cos (B) = 266 / 374
cos (B) = <span> <span> <span> 0.7112299465
Angle B =  </span></span></span>44.665 degrees








3 0
3 years ago
Can someone do these two questions for me please. I have a lot of homework to do and I'm trying to get a lot of questions done a
olga_2 [115]

Answer:

1. is 25

2. I think this one is 25 too?

Step-by-step explanation:

im working on the second

6 0
2 years ago
Read 2 more answers
Jay is cutting a roll of biscuit dough into slices that are 3/8 inch thick. If the roll is 101/2 inches long, how many slices ca
IceJOKER [234]
The roll of the biscuit is 101/2 inches long. It has to be cut into slices that are 3/8 inches thick.
Then
The number of slices = (101/2)/(3/8)
                                   = (101/2) * (8/3)
                                   = 808/6
                                   = 404/3
                                   = 134.66
So the biscuit dough can be cut into 134 slices approximately. A small part will be left. This is the only way to find out the number of slices the biscuit dough can be sliced into. Hope this helps you in understanding the way it is done.



4 0
2 years ago
5 yrs ago, Nuri was thrice as old as Sonu. 10 yrs later, Nuri will be twice as old Sonu. How old are Nuri n Sonu?​
Papessa [141]

Answer:

Answer will be 50

Step-by-step explanation:

Let us suppose, present age of Nuri be ‘x’ years and present age of Sonu be ‘y’ years.

Now, it is given that five years ago, Nuri was thrice old as Sonu. Hence,

Five years ago,

Nuri’s age = x-5 years

Sonu’s age = y-5 years

And relation between ages can be given as

Nuri’s age = 3×sonu’s age or

x-5 = 3(y-5)

x-5 = 3y-15

x-3y+10 = 0 ………..(i)

Another relation is given in the problem that ten years later, Nuri is twice as old as Sonu.

So, ten years ago,

Nuri’s Age = x+10

Sonu’s Age = y+10

And relation between ages can be written as

x+10 = 2(y+10)

x+10 = 2y+20

x-2y-10 = 0 …………..(ii)

Now we can solve the equation (i) and (ii) to get values of x and ‘y’ or present ages of Nuri and Sonu.

Value of ‘x’ from equation (i) be

x = 3y-10 ……….(iii)

Putting value of ‘x’ from equation (iii) in equation (ii) we get,

3y-10-2y-10 = 0

y = 20

Now, from equation (iii) value of ’x’ can be given as,

x= 3(20)-10

x = 50

Hence, the present ages of Nuri and Sonu are 50 years and 20 years respectively.

7 0
2 years ago
5/8 brainliest im giving if u get it right :D
blondinia [14]

Well basically if they lost 8 points and gained 6, they have -2 points.

3 0
2 years ago
Read 2 more answers
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