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jonny [76]
3 years ago
5

Can you help? What do you think ??

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
8 0

Answer:

The amount of money one may spend in a month may be greater than that of ones monthly payment especially when the payment is at a lower rate.

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(02.01)Line segment CD has a length of 3 units. It is translated 2 units to the right on a coordinate plane to obtain line segme
kipiarov [429]
The translation of a segment or object, from one location to another on the plane, doesn't change its length, just its location.

so it used to be there, now is here, but its length never changed.
7 0
3 years ago
Read 2 more answers
Consider a nine -year moving average used to smooth a time series that was first recorded in 1961. a. Which year serves as the f
kirill [66]

Answer:

  a.  1965

  b.  8 years

Step-by-step explanation:

For answers to questions like these it can work to consider the smallest possible dataset.

<h3>Dataset</h3>

For our purpose, consider the 9 years/values to be averaged to be ...

  1, 2, 3, 4, 5, 6, 7, 8 ,9

<h3>Observations</h3>

a. The center value of the data set is 5. Its number is 5-1=4 more than the first one.

The first centered value is from the year 1961 +4 = 1965.

b. The 4 values at the beginning, and the 4 values at the end do not have a corresponding "average" value. That is, 4+4 = 8 values in the series are lost with respect to the number of average values.

8 years of values are lost.

5 0
2 years ago
Sonya sells bracelets once a month at a flea market. The
marta [7]
$30 because if you add 30 to those numbers it would give you the next months amount.
3 0
3 years ago
The table below shows elevations of different locations in the world
S_A_V [24]
Positive I think that would be it
8 0
3 years ago
Read 2 more answers
If tn = 4n+1, find t1, t2, t3, and tn+1. Express tn+1−tn in its simplest form.
Doss [256]

Answer:

t_1=5

t_2=9

t_3=13

t_{n+1}-t_n=4

Step-by-step explanation:

We have that:

t_n=4n+1

When we substitute n=1, we get:

t_1=4*1+1=5

When we substitute n=2 we get:

t_2=4*2+1=9

When we substitute n=3, we get:

t_3=4*3+1=13

When we substitute n=n+1, we get:

t_{n+1}=4*(n+1)+1=4n+5

Now

t_{n+1}-t_n=4n+5-(4n+1)

We expand and simplify to obtain:

t_{n+1}-t_n=4n+5-4n-1

t_{n+1}-t_n=4

3 0
3 years ago
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