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sweet-ann [11.9K]
3 years ago
9

Subtract the equation m-3n/6m3n - m+3n/6m^3n

Mathematics
1 answer:
Sergio039 [100]3 years ago
3 0

Answer:

- n^2m(3 - m^2)/2

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Find the particular solution to y'=2sin(x) given the general solution is y=C-2cos(x) and the initial condition y(pi/3)=1
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ANSWER

The particular solution is:

y=2-2 \cos(x)

EXPLANATION

The given Ordinary Differential Equation is

y'=2 \sin(x)

The general solution to this Differential equation is:

y=C-2 \cos(x)

To find the particular solution, we need to apply the initial conditions (ICs)

y( \frac{\pi}{3} ) = 1

This implies that;

C-2 \cos( \frac{\pi}{3} ) = 1

C-2( \frac{1}{2} )= 1

C-1= 1

C= 1 + 1 = 2

Hence the particular solution is

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3 years ago
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Answer: If the measures of the corresponding sides of two triangles are proportional then the triangles are similar. Likewise if the measures of two sides in one triangle are proportional to the corresponding sides in another triangle and the including angles are congruent then the triangles are similar.

Step-by-step explanation:

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3 years ago
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UNO [17]

If a polynomial with real coefficient has a complex zero, the conjugate of that number will be a zero as well.

So, if 4-6i is a zero, 4+6i will be a zero as well

If -2+11i is a zero, -2-11i will be a zero as well

So, the zeroes are

\dfrac{1}{3},\ 4-6i,\ 4+6i,\ -2+11i,\ -2-11i

4 0
3 years ago
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Answer:

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Step-by-step explanation:

The value is 256 because 4^4 is 4*4*4*4 which equals 256 :))

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3 years ago
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3 years ago
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