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2 years ago

Necesito ayuda por fis

Mathematics

1 answer:

svet-max [94.6K]2 years ago

3 0

Answer:

pues que es en que necesitas ayuda

Step-by-step explanation:

dime namas comentame y te ayudo

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What’s 2x4+10-17•2067

AlekseyPX

The correct answer is 2067

7 0

3 years ago

Read 2 more answers

hector and Alex traded video games. Alex gave hector one fourth of his video games in exchange for 6 video games. then he sold 3

Anuta_ua [19.1K]

Answer:

he started with either 20 or 15 i probably thought about this way to much so this is the best i could come up with

Step-by-step explanation:

5 0

2 years ago

3) Given that lines a and b are parallel, and lines o and t are parallel, find the point

Crazy boy [7]

Answer:

X = 3°

Step-by-step explanation:

Since O and T are parallel you can use alternating lines

7x + 5° = 5x + 11° (alt. angles, O||T)

Move the 5x and the 5°

7x - 5x = 11° - 5°

2x = 6°

Divide both sides by 2

x = 3°

This is assuming 11 is an angle

3 0

2 years ago

HELP ASP Lucy has a jewelry business. To make a certain necklace, she spends $3.38 on materials and $5.57 on labor. She then sel

Nataliya [291]

$5.57 + 3.38 =$
$8.95
15.99 - 8.95 = 7.04

4 0

3 years ago

The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont

BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

$\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)$

and its cumulative distribution function (CDF) is

$\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}$

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

$\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347$

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so A∩B = B and

$\bf P(A | B) = P(B)P(B) = (P(B))^2$

We have

$\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237$

hence,

$\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313$

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

$\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}$

<em>Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection. </em>

This means that,

<em>Probability that at least one of them needs replacement at the first inspection = </em>

$\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021$

5 0

3 years ago

Necesito ayuda por fis​

Necesito ayuda por fis