Step-by-step explanation: look so if you have
shcool A its 8v+4b=12
and
School B: 12v+4b= 16
since both classes used 4 busses we can use elimination by subtracting the A class Equation from the b class equation to solve from v for its value Then, use either equation and the now found value for v to solve for b.
You should find part of the process to be
12v+4b-(8v+4b)=12-16 which shows the van holds only a few people even before continuing the solution.
Answer -4
Answer:
y= -a*x + 12
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>b</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>b</u>
Step-by-step explanation:
ax+by=12 (subtract "ax" from both sides so that the one on the left will become zero and we will have "by" )
by= -ax+12(divide both side by "by" so that we will have the equation as "y=mx+b")
finally the result will be:
y= -a*x + 12
b b
Answer:
c
Step-by-step explanation:
because I had a test on these
need 2 numbers when added = 5 and when multiplied = -24
answer is D
-3+8 = 5
-3*8 = -24
Answer:
6 2/3
Step-by-step explanation:
