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trapecia [35]
3 years ago
13

You are pulling up an anchor while on a boat. You pull up the anchor at a rate of 0.5 feet per second. After 6 seconds, the anch

or is 8 feet from your hands. Write an equation that represents the distance y (in feet) that the anchor is from your hands after x seconds. Then graph the equation.
Mathematics
1 answer:
lys-0071 [83]3 years ago
4 0

Answer:

the answer is 19

Step-by-step explanation:

8+6=14

14+5=19

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The quotient of (x^3+3x^2-4x-12)/(x^2+5x+6)
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Answer: The quotient is (x-2).

Step-by-step explanation:

Since we have given that

f(x)=(x^3+3x^2-4x-12)\\\\and\\\\g(x)=x^2+5x+6\\\\So,\ \frac{\left(x^3+3x^2-4x-12\right)}{\left(x^2+5x+6\right)}

Now, we have to find the quotient of the above expression.

So, here we go:

Factorise\ (x^3+3x^2-4x-12)\\\\=\left(x^3+3x^2\right)+\left(-4x-12\right)\\\\=-4\left(x+3\right)+x^2\left(x+3\right)\\\\=\left(x+3\right)\left(x^2-4\right)

Now, we will divide the above simplest form with g(x):

\frac{\left(x+3\right)\left(x^2-4\right)}{\left(x+2\right)\left(x+3\right)}\\\\=\frac{x^2-4}{x+2}\\\\=\frac{\left(x+2\right)\left(x-2\right)}{x+2}\ using\ (a^2-b^2)=(a+b)(a-b)\\\\=x-2

Hence, the quotient is (x-2).


6 0
3 years ago
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Step-by-step explanation: And the answer will be 3

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2 years ago
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