Question

Divide (-3х + 4 + 18х^2 )by (5 + 6x)

Answer 1

Answer:

The division will be represented as:

$\frac{18x^{2}-3x+4}{6x+5}=(3x-3)+\frac{19}{6x+5}$

Step-by-step explanation:

1) Let's find a number with a variable that multiplied by 6x gives as 18x². It will be 3x, because (6x+5)3x=18x²+15x.

Now, let's subtstract:

$(18x^{2}-3x+4)-(18x^{2}+15x)=-18x+4$

2) Let's find a number with a variable that multiplied by 6x gives as -18x. It will be -3, because (6x+5)(-3)=-18x-15.

Now, let's subtstract:

$(-18x+4)-(-18x-15)=19$  

Therefore, the division will be represented as:

$\frac{18x^{2}-3x+4}{6x+5}=(3x-3)+\frac{19}{6x+5}$

I hope it helps you!