"the argument" of a function, is simply "the expression being evaluated by that function".
Answer:
I can't solve and show it but only tell a method to do it!
So find the zero of the given factor:
i.e.

Now put its value (-1) in the polynomial

Now if the answer comes zero it is a factor.
You'll get your answer!
Answer:
{ - 1, 1, 7, 23 }
Step-by-step explanation:
To find the range substitute the values from the domain into g(x)
g(-2) = -2(- 2) + 3 = 4 + 3 = 7
g(- 10) = - 2(- 10) + 3 = 20 + 3 = 23
g(1) = - 2(1) + 3 = - 2 + 3 = 1
g(2) = - 2(2) + 3 = - 4 + 3 = - 1
Range is { - 1, 1, 7, 23 }
Answer:
x = 4
Step-by-step explanation:
a = i-2j
b = 2i-xj
1 = k•2
-2 = k•(-x)
=> 1/2 = k
=> (-2)/(-x) = k
=> 1/2 = (-2)/(-x) => 1/2 = 2/x => x = 4
Answer:
15 x^8 y^3
Step-by-step explanation:
The area of a rectangle is given by
A = l*w where l is the length and w is the width
A = ( 5x^6 y^2) *( 3x^2 y)
= 15 x^(6+2) y^(2+1)
= 15 x^8 y^3