Answer:
6. x = 15
7. JL = 78
Step-by-step explanation:
6. 8x - 23 = ½(10x + 44) (midsegment theorem)
Multiply both sides by 2
2(8x - 23) = 10x + 44
16x - 46 = 10x + 44
Collect like terms
16x - 10x = 46 + 44
6x = 90
Divide both sides by 6
x = 90/6
x = 15
7. MN = 5x - 16
JL = 4x + 34
MN = ½(JL) (midsegment theorem)
5x - 16 = ½(4x + 34) (substitution)
2(5x - 16) = 4x + 34
10x - 32 = 4x + 34
Collect like terms
10x - 4x = 32 + 34
6x = 66
x = 66/6
x = 11
JL = 4x + 34
Plug in the value of x
JL = 4(11) + 34 = 44 + 34
JL = 78
Cos(60) = cos(90 - 30) = sin(30) = 1/2
This should be what you want.
Answer:
20 chairs
Step-by-step explanation:
After 136 people are seated in the bleacher, there can be 514 people seated in chairs. We know that 514 = 25×20 +14, so there can be 20 rows of 25 chairs. We require an equal number of chairs in each row, so there cannot be some rows with 21 chairs, nor can there be a 26th row with 14 chairs.
There can be 20 chairs in each row.
Answer:
Part 1) 
Part 2) 
Step-by-step explanation:
The picture of the question in the attached figure
Part 1
Find the length side AB
we know that
----> by SOH (opposite side divided by the hypotenuse)
substitute the given values
solve for AB
Part 2
Find the length side AC
we know that
----> by TOA (opposite side divided by the adjacent side)
substitute the given values
solve for AC
