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Oduvanchick [21]
3 years ago
11

A lamp is connected to the power supply.

Physics
1 answer:
Vika [28.1K]3 years ago
5 0

Answer:

There are 45 turns in the secondary coil.

Explanation:

Given that,

Input potential of the lamp, V_{in}=5\ V

The output potential of the lamp, V_{out}=1.5\ V

Number of turns in primary coil, N_P=150

We need to find the number of turns needed on the secondary coil. We know that the ratio for a transformer is as follows :

\dfrac{V_{out}}{V_{in}}=\dfrac{N_s}{N_P}\\\\N_s=\dfrac{V_{out}N_P}{V_{in}}\\\\N_s=\dfrac{1.5\times 150}{5}\\\\N_s=45\

So, there are 45 turns in the secondary coil.

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t_2 = D_2/v_o

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d_2 = V_y × t_2

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Total deflection down is;

d = d_1 + d_2

d = [½ × (qE/m) × (D_1/v_o)²] + [(qE/m) × (D_1•D_2/(v_o)²)]

d = (qE/m•v_o²)[½(D_1)² + D_1•D_2]

Making q/m the subject, we have;

q/m = (d•v_o²)/[E((D_1²/2) + (D_1•D_2))]

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E = 800 N/C

d = 1.25 cm = 0.0125 m

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