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3 years ago

(15 POINTS) Victor drew a diagram to show the life cycle of a low-mass star.

Physics

2 answers:

EleoNora [17]3 years ago

9 0

Answer: White dwarf is the answer

Explanation: White dwarf is the answer because th stars and the nebula are forming a new baby white dwarf. hope this helps thanks.

Evgen [1.6K]3 years ago

4 0

The answer is c so the area can grow

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A car is traveling at 35.8 m/s. What acceleration would it have if it took 2.0 s to come to a complete stop?

nasty-shy [4]

Answer:

$\boxed {\boxed {\sf a= -17.9 \ m/s^2}}$

Explanation:

Acceleration is equal to the change in velocity over the change in time.

$a=\frac{v_f-v_i}{t}$

The initial velocity is 35.8 meters per second. The final velocity is 0 meters per second when the car comes to a complete stop. The time is 2.0 seconds.

$v_f= 0 \ m/s \\v_i= 35.8 \ m/s \\t= 2 \ s$

Substitute the values into the formula.

$a=\frac{0 \ m/s - 35.8 \ m/s }{2 \ s}$

Solve the numerator.

$a= \frac{ -35.8 \ m/s} {2 \ s}$

Divide.

$a= -17.9 \ m/s/s = -17.9 \ m/s^2$

The car's acceleration is -17.9 meters per square second. The acceleration is negative because the car was coming to a stop and slowing down.

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3 years ago

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lara31 [8.8K]

Explanation:

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3 years ago

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Anyone want to be f-r-i-e-n-d-s? ^^ (You may answer for fr/ee points! <3)

Nuetrik [128]

Answer:

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Explanation:

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2 years ago

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What do you need to build a working electric motor?

FrozenT [24]

Answer: D a source of electricity

Explanation: I have done that question please tell me if it is correct

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3 years ago

How much energy is needed to heat and melt 3.0 kg of copper initially at 83°C?

Ne4ueva [31]

As we know that in order to melt the copper we need to take the temperature of copper to its melting point

So here heat required to raise the temperature of copper is given as

$Q = ms\Delta T$

We know that

melting temperature of copper = 1085 degree C

Specific heat capacity of copper = 385 J/kg C

now we have

$Q = 3(385)(1085 - 83)$

$Q = 1157310 J$

$Q = 1157.3 kJ$

now in order to melt the copper we know the heat required is

$Q = mL$

here we know that

L = 205 kJ/kg

now from above formula

$Q = 3(205) kJ$

$Q = 615 kJ$

now total heat required will be

$Q = 1157.3 kJ + 615 kJ$

$Q = 1772.3 kJ$

As we know that

$1 Cal = 4.18 kJ$

now we have

$Q = \frac{1772.3}{4.18} = 430 KCal$

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2 years ago