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tester [92]
3 years ago
11

(15 POINTS) Victor drew a diagram to show the life cycle of a low-mass star.

Physics
2 answers:
EleoNora [17]3 years ago
9 0

Answer: White dwarf is the answer

Explanation: White dwarf is the answer because th stars and the nebula are forming a new baby white dwarf. hope this helps thanks.

Evgen [1.6K]3 years ago
4 0
The answer is c so the area can grow
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A ball falls for 9.0 s increasing its kinetic energy by 2700. If the force acting on the ball in 6.0 N find the following quanti
Ivanshal [37]

Answer:

Change in velocity:  88 m/s

Average velocity:  50 m/s

initial velocity:  5.9 m/s

Final velocity:  94 m/s

Initial momentum:  3.6 kg m/s

Final momentum: 58 kg m/s

Explanation:

Acceleration = change in velocity / time

9.8 m/s² = Δv / 9.0 s

Δv = 88 m/s

Work = change in energy

Fd = ΔE

(6.0 N) d = 2700 J

d = 450 m

Average velocity = distance / time

v_avg = 450 m / 9.0 s

v_avg = 50 m/s

v − v₀ = 88 m/s

½ (v + v₀) = 50 m/s

Solving the system of equations:

v + v₀ = 100 m/s

2v = 188 m/s

v = 94 m/s

v₀ = 5.9 m/s

Use Newton's second law to find the mass:

F = ma

6.0 N = m (9.8 m/s²)

m = 0.61 kg

Find the momentums:

p₀ = (0.61 kg) (5.9 m/s) = 3.6 kg m/s

p = (0.61 kg) (94 m/s) = 58 kg m/s

6 0
3 years ago
A girl on the outer edge of a merry-go-round moves in uniform circular motion. Which of the following is NOT correct?
nignag [31]
I think that from the answers above the answer is B.
7 0
3 years ago
Read 2 more answers
A 60 kg student is standing motionless. Approximately how much force is the floor exerting on the student?
Solnce55 [7]
The normal force is equal in magnitude and opposite in direction to the weight of the student.
W = m · g = 60 kg · 10 m/s² = 600 N ( downward )
N = - 600 N
Answer:
B ) 600 N upward.
7 0
3 years ago
Which statement about electrons and atomic orbitals is NOT true?
balandron [24]

<em>An electron has the same amount of energy in all orbitals  is not true</em>

\boxed{\boxed{\bold{Further~explanation}}}

In an atom there are levels of energy in the skin and sub skin.

  • This energy level is expressed in the form of electron configurations.

Writing electron configurations starts from the lowest to the highest sub-shell energy level.

So electrons that occupy the orbitals in the lowest sub-skin have the lowest energy level

  • In the principle of Pauli's prohibition it was stated that there are no two electrons in one atom that can have the same four quantum numbers.

So suppose that there are two electrons occupying one orbital can have the same main quantum number (n), azimuth (l) and magnetic (m), then the last quantum number that is the quantum spin number (s) must be different.

So that the two electrons are different from just the quantum spin number, even though the other quantum numbers are the same.

So in one orbital only a maximum of 2 electrons is occupied, because if there is a third electron, this third electron will have the same quantum spin number as the previous electron

  • The electron cloud is a visual representation of the location of electrons in an atom.

Orbital is the place around the nucleus where electrons may be found

Electron clouds show the state of electrons in their orbitals

So electron clouds can show the condition of all orbitals in an atom

The lowest energy level of an electron occupies a sub-skin of 1s which has only one orbital

Charging electrons in the sub skin uses the following sequence:

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.

Statement about electrons and atomic orbitals is not true is An electron has the same amount of energy in all orbitals

the electron configuration for barium (Ba) in noble-gas notation brainly.com/question/11147367

the formation of a bond.

brainly.com/question/11311275

quantum number

brainly.com/question/2292596

Keywords: the electron configuration, orbitals, atoms, energy, skin, sub skin, electron clouds

8 0
3 years ago
Read 2 more answers
What would you need to know to calculate the angular momentum of a man on a Ferris wheel?
valentinak56 [21]
The angular momentum calculated with respect to the axis of rotation of an object is given by:
L=mvr
where m is the object's mass, v is its tangential speed, and r is its distance from the axis of rotation.

In case of a man on a Ferris wheel, we need to have these quantities in order to calculate his angular momentum. These quantities corresponds to:
- m, the mass of the man
- v, the tangential speed of the wheel at its edge
- r, the radius of the wheel

It is possible to calculate the angular momentum even if we don't know v, the tangential speed. In this case, we need to know at least the angular velocity \omega (because from this relationship we can find the tangential speed: v=\omega r) or the period of rotation of the wheel, T (because we can find the angular velocity from it: \omega= \frac{2 \pi}{T}).
4 0
4 years ago
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