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lisov135 [29]
3 years ago
5

Consider the function f(x) = 20/√x and its second-degree polynomial P2 (x) = 20 - 10(x-1) + 7.5(x-1)^2 at x=0.8. Compute the val

ue of f(0.8) and P2 (0.8). Round your answer to four decimal places.(A) f(08) = 22.3607 P2(0.8) = 44.6000(B) f(08) = 22.3607 P2(0.8) = 22.3000(C) f(08) = 45.7214 P2(0.8) = 45.6000(D) f(08) = 21.3607 P2(0.8) = 21.3000(E) f(08) = 23.3607 P2(0.8) = 22.3000
Mathematics
1 answer:
krok68 [10]3 years ago
3 0

Answer:

f (0.8) = 22.3607 and P_{2} (0.8) = 22.300.

Step-by-step explanation:

According to the statement, f (x) = \frac{20}{\sqrt{x}}  and  P_{2}(x) = 20 - 10 (x-1) + 7.5 (x-1) ^ 2. Based on these definitions, at x=0.8 produce:

f (0.8) = \frac{20}{\sqrt {0.8}} = 22.3607.  On the other hand, you have to:

P_{2} (0.8) = 20 - 10 (0.8 -1) +7.5 (0.8 -1)^2

P_{2} (0.8) = 20 - 10 (-0.2) +7.5 (-0.2)^2 = 22.300

Then, it can be affirmed that f (0.8) = 22.3607 and P_{2} (0.8) = 22.300.

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