Answer:
g = 15
Step-by-step explanation:
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
7*g+8*(6*g+3)-(849)=0
Step by step solution :
Step 1 :
Step 2 :
Pulling out like terms :
2.1 Pull out like factors :
6g + 3 = 3 • (2g + 1)
Equation at the end of step 2 :
(7g + 24 • (2g + 1)) - 849 = 0
Step 3 :
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
55g - 825 = 55 • (g - 15)
Equation at the end of step 4 :
55 • (g - 15) = 0
Step 5 :
Equations which are never true :
5.1 Solve : 55 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
5.2 Solve : g-15 = 0
Add 15 to both sides of the equation :
g = 15
Hope this helps
Because we have two values of x, we can set the two expressions equal to each-other.
x^2 + 6x + 9 = x + 3
Subtract x and 3 from both sides.
x^2 + 5x + 6 = 0
Now that we have all terms on one side, we can find the values of x.
Using the AC method, we can simplify this equation to (x + 2)(x + 3)
The solutions to the system of equations presented are:
<h3>x = -2, x = -3.</h3>
Sin (30°) =

AB = sin (30°) x 96 = 48cm
Let 3<em>n</em> + 1 denote the "number" in question. The claim is that
(3<em>n</em> + 1)² = 3<em>m</em> + 1
for some integer <em>m</em>.
Now,
(3<em>n</em> + 1)² = (3<em>n</em>)² + 2 (3<em>n</em>) + 1²
… = 9<em>n</em>² + 6<em>n</em> + 1
… = 3<em>n</em> (3<em>n</em> + 2) + 1
… = 3<em>m</em> + 1
where we take <em>m</em> = <em>n</em> (3<em>n</em> + 2).
Answer:
The advertisement should use 16 minutes.
Step-by-step explanation:
Exponential distribution:
The exponential probability distribution, with mean m, is described by the following equation:

In which
is the decay parameter.
The probability that x is lower or equal to a is given by:

Which has the following solution:

The probability of finding a value higher than x is:

The manager of a fast-food restaurant determines that the average time that her customers wait for service is 3.5 minutes.
This means that 
What number of minutes should the advertisement use?
The values of x for which:

So






Rounding to the nearest number, the advertisement should use 16 minutes.