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2 years ago

13

Angie and Kenny play online video games. Angie buys 1 software package and 1month of gameplay. Kenny buys 1 software package and

2 months of gameplay. each software package costs $30. if their total cost is $90, what is the cost of one month of gameplay?

1 answer:

MakcuM [25]2 years ago

5 0

Answer:

10$ I think

Step-by-step explanation:

2*30=60

90-60=30

30/3=10

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9- (-2)<br><br><br>Do I add or use KFC?

Iteru [2.4K]

Answer:

the answer is 11

you need to add 9 with 2

i think the KFC thecnique cant be use in this question

3 0

3 years ago

Which expression is equivalent to 5y^3/(5y)^-2

Serggg [28]

Answer:

5^3 y^5

125 y^5

Step-by-step explanation:

5y^3/(5y)^-2

Distribute the exponent in the denominator

5y^3/(5 ^-2 y^-2)

A negative exponent in the denominator brings it to the numerator

5y^3 5 ^2 y^2

Combine like terms

5 * 5^2 * y^3 5^2

We know that a^b * a^c = a^(b+c)

5^(1+2) * y^( 3+2)

5^3 y^5

125 y^5

6 0

3 years ago

Solve the two-step equation. 5.1 = –3x – 4.2 1. Add 4.2 to both sides. 2. Divide both sides by -3. The solution is x = _________

Serggg [28]

Answer:

5.1 = -3x - 4.2

-3x - 4.2 = 5.1

-3x = 5.1 + 4.2

-3x = 9.3

x = 9.3/-3

x = -3.1

6 0

3 years ago

Read 2 more answers

Which of these is a complex number? <br><br> A. <br><br> B. <br><br> C. <br><br> D.

Step2247 [10]

Answer:

option D

$\frac{8}{3} + \sqrt{\frac{-7}{3} }$

Step-by-step explanation:

Given in the question are 4 number

5√1/3 - $\frac{9}{\sqrt{7} }$

2 - $\frac{1}{\sqrt{11} }$

9 + $3\sqrt{\frac{5}{2} }$

$\frac{8}{3} + \sqrt{\frac{-7}{3} }$

A Complex Number is a combination of a Real Number and an Imaginary Number

<h3>Example </h3>

a + ib

where a is real number

b is imaginary number

i is 'lota' which is √-1

<h3>So according to the definition above </h3>

$\frac{8}{3} + \sqrt{\frac{-7}{3} }$ is complex number in which

$\frac{8}{3}$ is real part

$\sqrt{\frac{7}{3} } \sqrt{-1}$ = $\sqrt{\frac{7}{3} } i$ is the imaginary part

7 0

3 years ago

If the point (a, b) is equidistant from the points (-a, 2) and (2, -b), then prove that 3(a+b)+4=0

erastova [34]

Answer: see proof below

<u>Step-by-step explanation:</u>

Since (a, b) is equidistant from (-a, 2) and (2, -b), then it is the midpoint of the those two points. Use Midpoint formula to find (a, b).

$M_x=\dfrac{x_1+x_2}{2}\qquad \qquad \qquad M_y=\dfrac{y_1+y_2}{2}\\\\\\a=\dfrac{-a+2}{2}\qquad \qquad \qquad \quad b=\dfrac{2-b}{2}\\\\\\2a=-a+2\qquad \qquad \qquad \quad 2b=2-b\\\\\\3a=2\qquad \qquad \qquad \qquad \qquad 3b=2\\\\\\a=\dfrac{2}{3}\qquad \qquad \qquad \qquad \qquad b=\dfrac{2}{3}$

3(a + b) - 4 = 0

$3\bigg(\dfrac{2}{3}+\dfrac{2}{3}\bigg)-4=0\\\\\\3\bigg(\dfrac{4}{3}\bigg)-4=0\\\\\\4-4=0\\\\0=0\qquad \text{TRUE!}$

<em>Notice that I changed the equation to "negative 4" because the equation you provided did not make a true statement.</em>

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4 0

3 years ago