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2 years ago

Create 5 problems using all operations that has a solution of 5

Mathematics

1 answer:

Iteru [2.4K]2 years ago

7 0

Answer:

((5*5) + (10-5) * (50/100)) ÷ 3 = 5

((4*4)+(17-8 *(1.378/2)) ÷ 3.445 = 5

Step-by-step explanation:

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AABC is isosceles.<br> AB = 3x - 4 and BC = 5x - 10.<br> AB = [?]

Schach [20]

If AB = BC then set up the equation 3x - 4 = 5x - 10

Subtract 3x.

-4 = 2x - 10

Add 10.

6 = 2x

Divide by 2.

3 = x

AB is 3x - 4 so

3(3) - 4

9 - 4

AB = 5

If AB is not equal to BC then this is not solvable.

But if they are I am sure AB = 5.

Hope this helps

4 0

3 years ago

Jed wants to earn 25% annual net income on his $50,000 cash investment in property his annual expense of owning the property are

Elena L [17]

Answer: $1,842

Step-by-step explanation:

John wants to earn 25% of his investment of $50,000 which is:

= 25% * 50,000

= $12,500

He has expenses of $9,600 yearly so the rent he should charge per year in order to make his 25% requirement as income is:

= Expenses + Return

= 9,600 + 12,500

= $22,100

Rent per month is:

= 22,100 / 12

= $1,842

8 0

3 years ago

Which exspression is equivalent to :

dlinn [17]

Answer:

Step-by-step explanation:

4 0

3 years ago

How many 2/5 cups of servings are in 10 cups of flour?

Inga [223]

10 / (2/5)...when dividing with fractions, flip what u r dividing by, then multiply
10 * 5/2 = 50/2 = 25...so there are 25 of them

3 0

2 years ago

In a bag of m&m's there are 5 brown 6 yellow 4 blue 3 green and 2 orange. What's the probability of getting 3 yellow m&m

olasank [31]

There are 5+6+4+3+2=20 m&m's in the bag.
Calculate in how many ways you can choose 3 m&m's from 20:
$_{20} C _3=\frac{20!}{3!(20-3)!}=\frac{20!}{3! \times 17!}=\frac{17! \times 18 \times 19 \times 20}{6 \times 17!}=\frac{18 \times 19 \times 20}{6}=3 \times 19 \times 20= \\
=1140$

There are 6 yellow m&m's.
Calculate in how many ways you can choose 3 m&m's from 6:
$_6 C _3 = \frac{6!}{3!(6-3)!}=\frac{6!}{3! \times 3!}=\frac{3! \times 4 \times 5 \times 6}{3! \times 6}=\frac{4 \times 5 \times 6}{6}=4 \times 5=20$

The probability is the number of ways of choosing 3 m&m's from 6 m&m's divided by the number of ways of choosing 3 m&m's from 20 m&m's.
$P=
\frac{20}{1140}=\frac{20 \div 20}{1140 \div 20}=\frac{1}{57}$

The probability is 1/57.

4 0

3 years ago

Create 5 problems using all operations that has a solution of 5​

Create 5 problems using all operations that has a solution of 5