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spayn [35]
3 years ago
8

Help&EXPLAIN Don’t use for points or will be reported and I’ll take the points back

Mathematics
1 answer:
anzhelika [568]3 years ago
6 0

Answer:

X=151

Step-by-step explanation:

1. 61+90= 151

-Combine the two given angles

2.180-151= 29

-Subtract the total of the two combined from 180 because all 3 angles of a triangle add up to 180.

-29 is your difference which is also the angle next to X.

3.180-29= 151

-To find angle X you subtract 29 from 180 because angle X and 29 are supplementary angles that add up to 180.

-Therefore X=151

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In class 9A the ratio of boys to girls is 3:4. if there are 12 boys,how many girls are there?​
Mamont248 [21]

16 girls. 12 divided by 4 is 3, so this means that you have to take 4 and multiply it by 4 which equals to 16.

3 0
3 years ago
Given: m∠AEB = 45° ∠AEC is a right angle. Prove: bisects ∠AEC.
Musya8 [376]
If angle AEC is 90° and angle AEB bisects it and is 45° that right there proves that angle AEB bisects angle AEC
5 0
3 years ago
Find the height of a cone with a diameter of 12 m whose volume is 226m Use 3.14 for pi and round your answer to the nearest mete
Sergeu [11.5K]

Answer:

6m

Step-by-step explanation:

h=3(/V πr^2)=3(226/ π·6^2)≈5.99484

round to 6

5 0
3 years ago
Two ships leave a harbor together, traveling on courses that have an angle of 135°40' between them. If they each travel 402 mile
mario62 [17]

Answer:

Therefore they are 734.106 miles apart.

Step-by-step explanation:

Given that ,

Two ships have a harbor together. The angle between two ships  is  135°40'. Each of two ships travel 402 miles.

It forms a isosceles triangle whose two sides are 402 miles and one angle is 135°40'. Since it is isosceles triangle then other two angles of the triangle is equal.

Let ∠B= 135°40', and AB = 402 miles , BC =  402 miles

Then the distance between the ships = AC

We know

The sum of all angles = 180°

⇒∠A+∠B+∠C=180°

⇒∠A+135°40'+∠C=180°

⇒2∠A= 180°- 135°40'      [ since ∠A=∠C]

⇒2∠A=44°60'

⇒∠A= 22°30'

Again we know that,

\frac{AB}{sin\angle C}=\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}

Taking last two ratio,

\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}

Putting the value of BC , AC ,∠A,∠B

\frac{402}{sin 22^\circ30'}=\frac{AC}{sin 135^\circ40'}

\Rightarrow AC=\frac{402 \times sin135^\circ40'}{sin 22^\circ30'}

         ≈734.106 miles

Therefore they are 734.106 miles apart.

3 0
3 years ago
Giving Brainliest If You answer this correct
Lubov Fominskaja [6]

Answer:

magnitude is always postive

so, it will be +2.5 , so C

8 0
3 years ago
Read 2 more answers
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