X=5 y=15 (5,15).
This is how you do it:
-4(2x+3y=55): -8x-12y=-220
3(9x+4y=105):27x+12y=315
You add the two new equations together, canceling out the y values, and get the x value. Then, you go back and plug in the x value in the original equation to get the y value.
Angle a is 22.62 degrees
and
angle b is 67.38 degrees
X/2 >= -4
x >= -4 * 2
x >= -8
Answer:
a) 2.9%
b) Option B is correct.
The prisoners must be independent with regard to recidivism.
Step-by-step explanation:
Probability that one prisoner goes back to prison = 17% = 0.17
a) The probability that two prisoners released both go back to prison = 0.17 × 0.17 = 0.0289 = 2.89% = 2.9% to 1 d.p
b) The only assumption taken during the calculation is that probability of one of the prisoners going back to prison has no effect whatsoever in the probability that another prisoner goes back to prison. That is the probability that theses two events occur are totally independent of each other.
If they weren't, we wouldn't be able to use 0.17 as the probability that the other prisoner goes back to prison too.
Answer:
Step-by-step explanation:
We are to show that 1/1-sin theta + 1/1+cos theta = 2×sec square theta
Starting from the left hand side of the expression:
1/1-sin theta + 1/1+cos theta
Find the LCM
![\frac{1}{(1 -sin \theta) (1+cos \theta)} \\\\= \frac{1+cos \theta + 1 -sin \theta ]}{(1 -sin \theta) (1+cos \theta)} \\ = \frac{2+cos \theta - sin \theta}{1+cos \theta - sin \theta - sin \theta cos \theta}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%281%20-sin%20%5Ctheta%29%20%281%2Bcos%20%5Ctheta%29%7D%20%5C%5C%5C%5C%3D%20%5Cfrac%7B1%2Bcos%20%5Ctheta%20%2B%201%20-sin%20%5Ctheta%20%5D%7D%7B%281%20-sin%20%5Ctheta%29%20%281%2Bcos%20%5Ctheta%29%7D%20%5C%5C%20%3D%20%5Cfrac%7B2%2Bcos%20%5Ctheta%20-%20sin%20%5Ctheta%7D%7B1%2Bcos%20%5Ctheta%20-%20sin%20%5Ctheta%20-%20sin%20%5Ctheta%20cos%20%5Ctheta%7D)
