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3 years ago

Steve is analyzing two linear functions, f(x) and g(x). Will they intersect?

1 answer:

6 0

We get for x=2, f(2)=3, (f(x)=x+1) and g(2)=3, that means that they intersect at the moint M(3,3), so the answer is
(a)Yes, at a point with a positive x-coordinate

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Can someone help me with this one ?

Shalnov [3]

Step-by-step explanation:

Using pythagoras theorem

9^2 - 6^2 = x^2

Therefore X^2 = 81 - 36

= 45

Thus X = √45

X = 6.71

5 0

3 years ago

Solve for x in simplest form. 14 = 1/3(8x + 6)

elena-s [515]

Answer:

x = 4.5

Step-by-step explanation:

14 = 8/3x + 2

12 = 8/3x

36 = 8x

x = 4.5

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3 years ago

The total surface area of a cube is 96cm2, find its volume.

Setler [38]

Answer:

$\huge\boxed{V=64cm^3}$

Step-by-step explanation:

The formula of a surface area of a cube:

$SA=6a^2$

The formula of a volume of a cube:

$V=a^3$

We have

$SA=96cm^2$

Calculate the edge length (a).

$6a^2=96$ divide both sides by 6

$a^2=16\to a=\sqrt{16}\\\\a=4(cm)$

Calculate the volume of a cube:

$V=4^3=64(cm^3)$

6 0

3 years ago

Help me !!! Please someone

topjm [15]

Answer:

5 and 6

Step-by-step explanation:

The square root of 25 is 5 and the square root of 36 is 6. 33 falls between those

4 0

3 years ago

A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first the

Svetlanka [38]

Answer:

The hotel charge in each city before tax was $5125 of the first city and $3625 of the second city.

Step-by-step explanation:

Given:

A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first.

The tax of the first city was 6% and the tax of the second city was 10%.

Total hotel tax paid for two cities with $670.

Now, to find the hotel charge in each city before tax.

Let the hotel charge in first city before tax be $x.$

And the hotel charge in second city before tax be $y.$

So, as the hotel charge of the second city was 1500 higher than the first.

Thus,

$y=x-1500$ ........(1)

And as given, the tax of the first city was 6% and the tax of the second city was 10%, total hotel tax paid for two cities with $670.

6% of $x$ + 10% of $y$ = $670.

$\frac{6x}{100} +\frac{10y}{100} =670$

$0.06x+0.10y=670$

Substituting the value of $y$ from equation (1) we get:

$0.06x+0.10(x-1500)=670$

$0.06x+0.10x-150=670$

$0.16x-150=670$

Adding both sides by 150 we get:

$0.16x=820$

Dividing both sides by 0.16 we get:

$x=5125.$

The hotel charge in first city before tax = $5125.

Now, substituting the value of $x$ in equation (1) we get:

$y=x-1500$

$y=5125-1500$

$y=3625.$

The hotel charge in second city before tax = $3625.

Therefore, the hotel charge in each city before tax was $5125 of the first city and $3625 of the second city.

5 0

3 years ago