Answer:
a trend line can be used to make predictions in real-world situations (the third option)
Explanation:
the first & second options are wrong because it is not a requirement for a trend line to pass through any given data point.
the fourth option is wrong because a trend line shows the general upward/downward trend of the data, and may not necessarily touch all of the data points.
the third option is correct because a trend line helps to roughly estimate the trend (hence the name) of the graph, which allows us to make predictions in real-world situations.
i hope this helps! :D
Answer: 1. x = (y - 2)² + 8
3. y = 2(x +9)² + 7
<u>Step-by-step explanation:</u>
Notes: Vertex form is: y =a(x - h)² + k or x =a(y - k)² + h
- (h, k) is the vertex
- point of vertex is midpoint of focus and directrix:
- p is the distance from the vertex to the focus
1)
Now let's find the a-value:
Now, plug in a = 1 and (h, k) = (-8, 2) into the equation x =a(y - k)² + h
x = (y - 2)² + 8
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2)
Now let's find the a-value:
Now, plug in a = -1/2 and (h, k) = (1, 10) into the equation x =a(y - k)² + h
***************************************************************************************
3)
Now let's find the a-value:
Now, plug in a = 2 and (h, k) = (-9, 7) into the equation y =a(x - h)² + k
y = 2(x +9)² + 7
To solve for the confidence interval for the true average
percentage elongation, we use the z statistic. The formula for confidence
interval is given as:
Confidence interval = x ± z σ / sqrt (n)
where,
x = the sample mean = 8.63
σ = sample standard deviation = 0.79
n = number of samples = 56
From the standard distribution tables, the value of z at
95% confidence interval is:
z = 1.96
Therefore substituting the known values into the
equation:
Confidence interval = 8.63 ± (1.96) (0.79) / sqrt (56)
Confidence interval = 8.63 ± 0.207
Confidence interval = 8.42, 8.84
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The answer would be 9 because
Answer:
4/9
Step-by-step explanation: