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Masja [62]
3 years ago
9

Can someone help me please

Mathematics
2 answers:
tangare [24]3 years ago
5 0

Answer:

| - 16 |

Step-by-step explanation:

The absolute value function always gives a positive value, that is

| - a | = | a | = a

Then

| 6 | = 6

| - 16 | = | 16 | = 16

Thus the largest number from the list is | - 16 |

Alborosie3 years ago
5 0
I think |-16| because of its absolute value
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Does each equation represent exponential decay or exponential growth?
Elden [556K]

Answer:

  decay: a, b

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Step-by-step explanation:

A function is exponential if it has the independent variable in an exponent. g(x) is a linear function, not an exponential function.

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An exponential function is a growth function if the coefficient of the variable is positive and the base of the exponent is greater than 1. It is a decay function if the exponent is positive and the base is less than 1.

The first two functions are decay functions. The remaining four exponential functions are growth functions.

8 0
2 years ago
Find the quotient in simplest form.<br><br><br> 6 ÷ 2/3<br> A. 4<br> B. 8<br> C. 9<br> D. 12
olganol [36]

Answer:

C. 9

Step-by-step explanation:

6 ÷ 2/3

Copy dot flip

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7 0
3 years ago
Please answer the two questions!
shutvik [7]

Given:

The expressions are

(c) \left\{\left(\dfrac{2^4\times 3^6}{12^2}\right)^0\right\}^3

(d) \dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}

To find:

The simplified form of the given expression.

Solution:

(c)

We have,

\left\{\left(\dfrac{2^4\times 3^6}{12^2}\right)^0\right\}^3

We know that, zero to the power of a non-zero number is always 1. So, \left(\dfrac{2^4\times 3^6}{12^2}\right)^0=1

\left\{\left(\dfrac{2^4\times 3^6}{12^2}\right)^0\right\}^3=(1)^3

\left\{\left(\dfrac{2^4\times 3^6}{12^2}\right)^0\right\}^3=1

Therefore, the value of the given expression is 1.

(d)

We have,

\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}

It can be written as

\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}=\dfrac{13^3\times 1}{(65\times 49)^2}

\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}=\dfrac{13\times 13\times 13}{(65\times 49)(65\times 49)}

\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}=\dfrac{13}{(5\times 49)(5\times 49)}

\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}=\dfrac{13}{60025}

\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}=\dfrac{13}{60025}

Therefore, the value of given expression is \dfrac{13}{60025}.

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