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3 years ago

AC if TC = 20q + 10q^2?

Mathematics

1 answer:

Alexus [3.1K]3 years ago

4 0

Answer:

AC = (20+ 10q)

Step-by-step explanation:

Given that,

Total cost, TC = 20q + 10q²

We need to find AC i.e. average cost.

It can be solved as follows :

$AC=\dfrac{TC}{q}\\\\AC=\dfrac{20q + 10q^2}{q}\\\\AC=\dfrac{q(20+ 10q)}{q}\\\\AC={(20+ 10q)}$

So, the value of AC is (20+ 10q).

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In △ABC acute angles are in the ratio 5:1, i.e. ∠BAC:∠ABC = 5:1. If CH is an altitude and CL is an angle bisector, find m∠HCL.

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