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nadezda [96]
3 years ago
14

Which juice container is larger 2 L or 1 gallon

Mathematics
1 answer:
ANEK [815]3 years ago
7 0
The answer is 1 gallon is bigger than 2 L
You might be interested in
Hi guys, Can anyone help me with this tripple integral? Thank you:)
OleMash [197]

I don't usually do calculus on Brainly and I'm pretty rusty but this looked interesting.

We have to turn K into the limits of integration on our integrals.

Clearly 0 is the lower limit for all three of x, y and z.

Now we have to incorporate

x+y+z ≤ 1

Let's do the outer integral over x.  It can go the full range from 0 to 1 without violating the constraint.  So the upper limit on the outer integral is 1.

Next integral is over y.  y ≤ 1-x-z.   We haven't worried about z yet; we have to conservatively consider it zero here for the full range of y.  So the upper limit on the middle integration is 1-x, the maximum possible value of y given x.

Similarly the inner integral goes from z=0 to z=1-x-y

We've transformed our integral into the more tractable

\displaystyle \int_0^1 \int_0^{1-x} \int _0^{1-x-y} (x^2-z^2)dz \; dy \; dx

For the inner integral we get to treat x like a constant.

\displaystyle \int _0^{1-x-y} (x^2-z^2)dz = (x^2z - z^3/3)\bigg|_{z=0}^{z= 1-x-y}=x^2(1-x-y) - (1-x-y)^3/3

Let's expand that as a polynomial in y for the next integration,

= y^3/3 +(x-1) y^2 + (2x+1)y -(2x^3+1)/3

The middle integration is

\displaystyle \int_0^{1-x} ( y^3/3 +(x-1) y^2 + (2x+1)y -(2x^3+1)/3)dy

= y^4/12 + (x-1)y^3/3+ (2x+1)y^2/2- (2x^3+1)y/3 \bigg|_{y=0}^{y=1-x}

= (1-x)^4/12 + (x-1)(1-x)^3/3+ (2x+1)(1-x)^2/2- (2x^3+1)(1-x)/3

Expanding, that's

=\frac{1}{12}(5 x^4 + 16 x^3 - 36 x^2 + 16 x - 1)

so our outer integral is

\displaystyle \int_0^1 \frac{1}{12}(5 x^4 + 16 x^3 - 36 x^2 + 16 x - 1) dx

That one's easy enough that we can skip some steps; we'll integrate and plug in x=1 at the same time for our answer (the x=0 part doesn't contribute).

= (5/5 + 16/4 - 36/3 + 16/2 - 1)/12

=0

That's a surprise. You might want to check it.

Answer: 0

6 0
2 years ago
Find the area of the regular 18-gon with a radius of 3 mm. <br> Round to the nearest tenth.
marta [7]

Answer:

this becomes 1/2 * 6 * tan(10) * 3 which results in the area of one of the isosceles triangles is equal to 1.586942826 square units. since there are 18 of these isosceles triangles in the polygon, then multiply this by 18 to get area of the polygon with 18 sides is equal to 28.56497087 square units.

Follow me please

Mark brainliest

7 0
2 years ago
Find the curved surface area of a cone of radius 7cm and height 24cm
iVinArrow [24]

Right circular cone

Solve for surface area

A≈703.72cm²

r Radius

7

cm

h Height

24

cm

Answer:

Step-by-step explanation: their go your answer plz let me know got right then so plz rate me the  most brainlest preson

3 0
3 years ago
Which equation shows the value of -1.5 - 2.75?
VashaNatasha [74]
The answer is -1.5+(-2.75)=-4.25. This equation is the same as the result of -1.5 -2.75.
4 0
3 years ago
Read 2 more answers
Sam purchased a video game for $19.99 but paid $22.65. Sam paid $<br> in sales tax.
yulyashka [42]
He paid $2.66 in sales tax to find the correct answer you take 22.65-19.99 equals 2.66
3 0
2 years ago
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