Answer:
<em>the answer is K for #9</em>
Step-by-step explanation:
Answer:

Step-by-step explanation:
Hello,
a and b are the zeros, we can say that

So we can say that

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b
for instance we can write

and we can notice that
so
![(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab](https://tex.z-dn.net/?f=%28x-2a-3b%29%28x-3a-2b%29%3Dx%5E2-5%28a%2Bb%29x%2B6%5B%28a%2Bb%292-2ab%5D%2B13ab%5C%5C%3D%20x%5E2-5%28a%2Bb%29x%2B6%28a%2Bb%29%5E2%2Bab)
it comes

multiply by 3

Answer:
87.92 in²
Step-by-step explanation:
pi × (R² - r²) = area
Where R is the radius of the outer circle and r of the inner circle.
Since C = 2pi×r
37.68 = 2×3.14×r
r = 6 in
R = 6 + 2 = 8 in
Therefore,
pi × (R² - r²) = area
Area = 3.14 (8² - 6²)
= 87.92 in²
Subtract 100,000 by 82,052
If you do this correctly the answer would be 17,948 dollars.
Answer:
6.75.
Step-by-step explanation:
Following PEMDAS, as there are no other variables, we move from right to left. 9 x 3 is 27, and 27 / 4 is 6.75.
Hope this helps!