For a 50 kg person receives an absorbed dose of gamma radiation of 20 millirads, the total energy absorbed is mathematically given as
E=0.1457J
<h3>What is the total energy absorbed?</h3>
Generally, the equation for the total energy absorbed is mathematically given as
E=mass*gamma radiation
Therefore
E=50*20*19^{-3}
E=0.1457J
In conclusion, the total energy absorbed
E=0.1457J
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brainly.com/question/13439286
An ion is created by the transfer of electrons. The metals give away the elections and become positively charged. The non - metals take on electrons.
Balance.
So an ion is any atom that either gives away or takes on electrons.
Hello!
Recall the period of an orbit is how long it takes the satellite to make a complete orbit around the earth. Essentially, this is the same as 'time' in the distance = speed * time equation. For an orbit, we can define these quantities:
← The circumference of the orbit
speed = orbital speed, we will solve for this later
time = period
Therefore:
![T = \frac{2\pi r}{v}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B2%5Cpi%20r%7D%7Bv%7D)
Where 'r' is the orbital radius of the satellite.
First, let's solve for 'v' assuming a uniform orbit using the equation:
![v = \sqrt{\frac{Gm}{r}}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B%5Cfrac%7BGm%7D%7Br%7D%7D)
G = Gravitational Constant (6.67 × 10⁻¹¹ Nm²/kg²)
m = mass of the earth (5.98 × 10²⁴ kg)
r = radius of orbit (1.276 × 10⁷ m)
Plug in the givens:
![v = \sqrt{\frac{(6.67*10^{-11})(5.98*10^{24})}{(1.276*10^7)}} = 5590.983 m/s](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B%5Cfrac%7B%286.67%2A10%5E%7B-11%7D%29%285.98%2A10%5E%7B24%7D%29%7D%7B%281.276%2A10%5E7%29%7D%7D%20%3D%205590.983%20m%2Fs)
Now, we can solve for the period:
![T = \frac{2\pi (1.276*10^7)}{5590.983} =\boxed{ 14339.776 s}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B2%5Cpi%20%281.276%2A10%5E7%29%7D%7B5590.983%7D%20%3D%5Cboxed%7B%2014339.776%20s%7D)
Answer:
a
![F_A =425.42 \ N](https://tex.z-dn.net/?f=F_A%20%20%3D425.42%20%5C%20N)
b
![F_A_H = 358.58 \ N](https://tex.z-dn.net/?f=F_A_H%20%20%3D%20358.58%20%5C%20N)
Explanation:
From the question we are told that
The diameter of the Ferris wheel is ![d = 80 \ ft = \frac{80}{3.281} = 24.383](https://tex.z-dn.net/?f=d%20%20%3D%20%2080%20%5C%20ft%20%3D%20%20%5Cfrac%7B80%7D%7B3.281%7D%20%3D%20%2024.383)
The period of the Ferris wheel is ![T = 24 \ s](https://tex.z-dn.net/?f=T%20%20%3D%20%2024%20%5C%20s)
The mass of the passenger is ![m_g = 40 \ kg](https://tex.z-dn.net/?f=m_g%20%20%3D%20%2040%20%5C%20kg)
The apparent weight of the passenger at the lowest point is mathematically represented as
![F_A_L = F_c + W](https://tex.z-dn.net/?f=F_A_L%20%20%3D%20%20F_c%20%20%2B%20W)
Where
is the centripetal force on the passenger, which is mathematically represented as
![F_c =m * r * w^2](https://tex.z-dn.net/?f=F_c%20%20%3Dm%20%2A%20%20r%20%2A%20%20w%5E2)
Where
is the angular velocity which is mathematically represented as
![w = \frac{2* \pi }{T}](https://tex.z-dn.net/?f=w%20%3D%20%20%5Cfrac%7B2%2A%20%5Cpi%20%20%20%7D%7BT%7D)
substituting values
![w = \frac{2* 3.142 }{24}](https://tex.z-dn.net/?f=w%20%3D%20%20%5Cfrac%7B2%2A%203.142%20%7D%7B24%7D)
![w = 0.2618 \ rad/s](https://tex.z-dn.net/?f=w%20%3D%20%200.2618%20%5C%20rad%2Fs)
and r is the radius which is evaluated as ![r = \frac{d}{2}](https://tex.z-dn.net/?f=r%20%3D%20%20%5Cfrac%7Bd%7D%7B2%7D)
substituting values
![r = \frac{24.383}{2}](https://tex.z-dn.net/?f=r%20%3D%20%20%5Cfrac%7B24.383%7D%7B2%7D)
![r = 12.19 \ ft](https://tex.z-dn.net/?f=r%20%3D%2012.19%20%5C%20ft)
So
![F_c = 40 * 12.19* (0.2618)^2](https://tex.z-dn.net/?f=F_c%20%20%3D%2040%20%2A%2012.19%2A%20%280.2618%29%5E2)
![F_c = 33.42 \ N](https://tex.z-dn.net/?f=F_c%20%20%3D%20%2033.42%20%5C%20N)
W is the weight which is mathematically represented as
![W = 40 * 9.8](https://tex.z-dn.net/?f=W%20%3D%20%2040%20%2A%209.8)
![W = 392 \ N](https://tex.z-dn.net/?f=W%20%3D%20%20392%20%5C%20N)
So
![F_A = 33.42 + 392](https://tex.z-dn.net/?f=F_A%20%20%20%20%3D%20%2033.42%20%2B%20392)
![F_A =425.42 \ N](https://tex.z-dn.net/?f=F_A%20%20%3D425.42%20%5C%20N)
The apparent weight of the passenger at the highest point is mathematically represented as
![F_A_H = W- F_c](https://tex.z-dn.net/?f=F_A_H%20%20%3D%20%20W-%20F_c)
substituting values
![F_A_H = 392 - 33.42](https://tex.z-dn.net/?f=F_A_H%20%20%3D%20392%20-%20%2033.42)
![F_A_H = 358.58 \ N](https://tex.z-dn.net/?f=F_A_H%20%20%3D%20358.58%20%5C%20N)
Answer: B or "diamonds are rare,valuable gems".
Explanation:
since the link does not show very much, I don't know if A is correct or not. D is incorrect because that is an opinion. C is incorrect.