HElP I NEED TO turn this in

A block of mass 0.490 kg is pushed against a horizontal spring of negligible mass until the spring is compressed a distance x. T

Dennis_Churaev [7]

Answer:

The value of x is $x = 0.1955\ m$

The value of the velocity at the top is $v_{top} = 2.25 \ m/s$

Explanation:

The diagram of this process is on the first uploaded image

From the question we are told that

The mass of the block is $m_b = 0.490kg$

The distance of compression is $x$

The force constant is $k = 450 N/m$

The radius of the circular track is $R =1.00m$

The speed at the bottom of the track is $v_A = 13.4 \ m/s$

The frictional force experienced is $F_f = 7.00 \ N$

Now looking at this process we see that the potential energy of the spring is been transformed into the kinetic energy of the block . So,

$PE \ of \ spring = KE \ of \ block$

mathematically i.e

$\frac{1}{2}k x^2 = \frac{1}{2} m_bv^2_A$

$0.5 * 450 * x^2 = 0.5 * 0.490 * 13.4^2$

Making x the subject of the formula

$x = \sqrt{\frac{0.5 * 0.490 * 13.4^2}{ 0.5 * 450} }$

$= 0.1955\ m$

The average workdone by friction is $W_f = F_f * \pi$

Here $\pi is \ the\ net\ displacement$

$W_f = 7 * 3.142$

$= 21.99 J$

The kinetic energy at the bottom is

$KE = \frac{1}{2} * 0.490 * 13.4^2$

$= 43.99 \ N$

The potential energy gained at the top of the circle is

$PE = m_bgh$

Here h is the height which is equal to d(diameter) = 2r = 2 × 1 = 2 m and

g is acceleration due to gravity $= 9.8m/s^2$

Now substituting values

$PE = 0.490 * 9.8 *2$

$=9.604 J$

Since energy is can not be created nor destroyed but transformed according to first law of thermodynamics

$KE_{at \bottom} = PE _ {\ at \ top } + W_f + KE_{\ at \ top}$

$43.99 = 9.604 +21.99 + [\frac{1}{2} m_b * v_{top} ^2]$

$12.369= [2.45* v_{top} ^2]$

$v_{top} =\sqrt{\frac{12.369}{2.45} }$

$= 2.25 \ m/s$

8 0

3 years ago

The scientific method is? (apex)

Tcecarenko [31]

Answer:

C. The procedure scientist use to gain knowledge about the ohysical world

Explanation:

7 0

3 years ago

Read 2 more answers

Collaborative learning activities:__________.

blagie [28]

Answer:

Options A, B as well as C are the correct choices.

Explanation:

Collaborative learning seems to be a circumstance where learning is an educational approach as well as make an effort to understand all this together.
Except for personal learning, people participating in this learning draw mostly on competencies and qualifications of each other.

This form of learning isn't always linked to the perhaps one given choice. And the response to the above will still be the appropriate one.

3 0

3 years ago

how you could calculate a time step (dt) if you have a vector of accumulative distance (ie the distance keeps adding every step)

lakkis [162]

Answer:

dt = ds/dv.

Explanation:

to calculate the time step if you have a vector of accumulative distance and instanteneous velocity vector can be expressed bellow

solution

ds = dv/dt

divide the step distance by the instantaneous velocity you will get the time step.