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Vera_Pavlovna [14]
3 years ago
10

What substances were found in the innermost regions (within about the inner 0.3 AUAU) of the solar system before planets began t

o form?
Physics
1 answer:
julsineya [31]3 years ago
6 0

Answer:

Hydrogen and helium compounds.

Explanation:

We know that the solar System was formed around <u>4.6 billion years ago, </u>due to the gravitational collapse of a giant interstellar molecular cloud.

This cloud  is a type of interstellar cloud and its density and size permit the formation of molecules, most commonly molecular hydrogen.

Therefore the principal substances were found before planets began to form are hydrogen and helium compounds, besides Rocks, metals, most of them in gaseous form.

I hope it helps you!

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The total resistance of the circuit <br>​
ZanzabumX [31]

The total resistance of a series circuit is equal to the sum of individual resistances. Voltage applied to a series circuit is equal to the sum of the individual voltage drops. The voltage drop across a resistor in a series circuit is directly proportional to the size of the resistor.

If you know the total current and the voltage across the whole circuit, you can find the total resistance using Ohm's Law: R = V / I. For example, a parallel circuit has a voltage of 9 volts and total current of 3 amps. The total resistance RT = 9 volts / 3 amps = 3 Ω

Current: The total circuit current is equal to the sum of the individual branch currents. Resistance: Individual resistances diminish to equal a smaller total resistance rather than add to make the total.

4 0
3 years ago
Read 2 more answers
Calculate the pressure the fluid exerted on your diver. The acceleration of gravity is 9.8 m/s2 and the density of the water is
erica [24]

Complete question:

A diver is 10 m below the surface of water. Calculate the pressure the fluid exerted on the diver. The acceleration of gravity is 9.8 m/s2 and the density of the water is 1000 kg/m3. Answer in units of Pa. Show your work.

Answer:

Tthe pressure the fluid exerted on the diver is 1.99 x 10⁵ Pa

Explanation:

Given;

density of water, ρ = 1000 kg/m³

diver's position below the surface of the water, h = 10 m

acceleration due to gravity, g = 9.8 m/s²

Let the atmospheric pressure, P₀ = 101325 Pa

The pressure 10 m below the surface of the water is calculated as;

P =  P₀  + ρgh

P = 101325 Pa  +  (1000 x 9.8 x 10)Pa

P = 199325 Pa

P = 1.99 x 10⁵ Pa.

Therefore, the pressure the fluid exerted on the diver is 1.99 x 10⁵ Pa

5 0
3 years ago
You shine a LASER from the air into water. What happens to light?
GarryVolchara [31]
The answer is B! Hope this helps
5 0
3 years ago
A Rac variant, in which the residue at position 61 was replaced with an alanine (Rac61A), was synthesized. Wild-type Rac and Rac
ludmilkaskok [199]

Answer:

Ammonia, (NH_{3})

Explanation:

If a Rac variant, in which the residue at position 61 was replaced with an alanine (Rac-61A), was synthesized. Also, Wild-type Rac and Rac-61A were incubated separately with VopC.

In order to obtain data to support that VopC modifies Rac at residue 61, the samples should be analyzed for the presence of Ammonia (NH_{3}[\tex]) compound.In chemistry, the Vanadyl Phthalocyanine (VopC) comprises of a catalytic domain that activates host cells GTPase Rac irreversibly, through the deamide side chain of the residue existing at position 61.Also, we know that a deamidation reaction gives off Ammonia, [tex](NH_{3}) and as such when ammonia is present in the sample containing Wild-type Rac but not in Rac-61A, this simply proves or provide the data to support that VopC modifies Rac at residue 61.

<em>Additionally, deamidation can be defined as the chemical conversion (hydrolysis) of an amide functional group such as glutamine, asparagine, in a polypeptide to another functional group such as glutamic acid or isoaspartic acid respectively by treating it with a strong acid (deamidate, transamidase). </em>

3 0
3 years ago
A vector has an x-component of -7.55m and a y-component of -2.48. Find the direction of the vector
Sedbober [7]

Answer:

198.2°

Explanation:

The angle from the +x axis can be found with:

θ = atan(vy / vx)

Given vx = -7.55 and vy = -2.48:

θ = atan(-2.48 / -7.55)

θ = 18.2°, 198.2°

Since θ is in the third quadrant, θ = 198.2°.

8 0
3 years ago
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