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Alexus [3.1K]
3 years ago
11

The average power dissipated in a 47 ω resistor is 2.0 w. what is the peak value i 0 of the ac current in the resistor?

Physics
1 answer:
pishuonlain [190]3 years ago
4 0
The average dissipated power in a resistor in a ac circuit is:
P=I_{rms}^2 R
where R is the resistance, and I_{rms} is the root mean square current, defined as
I_{rms} =  \frac{I_0}{\sqrt{2}}
where I_0 is the peak value of the current. Substituting the second formula into the first one, we find
P=( \frac{I_0}{\sqrt{2} } )^2 R =  \frac{1}{2} I_0^2 R
and if we re-arrange this formula and use the data of the problem, we can find the value of the peak current I0:
I_0 =  \sqrt{ \frac{2 P}{R} }=  \sqrt{ \frac{2 \cdot 2.0 W}{47 \Omega} }=0.29 A
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Answer:

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Explanation:

Given the following data;

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To find how long is the sound wave, we would determine its wavelength;

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Ms. Garcia’s car can go from rest to 25 m/s in 10 seconds. The car’s velocity changes at a uniform rate. How far does the car tr
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We will use this equation:

s = 1/2*a*t^2 + v0*t + s0

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a = acceleration

t = time

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In this case::

v0 = 0

s0 = 0

So our equation will look like that now:

s = 1/2 * a * t^2

let's calculate the acceleration first of all:

a = (vf - vi) / t

where vf is the final speed and vi is the initial speed. t is the time.

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Now we can calculate the space:

s = 1/2 * (2.5 m/s^2) * (10s)^2 = 125m

---

Hope it was helpful! Have a great day.

4 0
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