Answer:

Step-by-step explanation:
GIVEN: A farmer has
of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one side of the pen. The length of the barn is
.
TO FIND: Determine the dimensions of the rectangle of maximum area that can be enclosed under these conditions.
SOLUTION:
Let the length of rectangle be
and
perimeter of rectangular pen 


area of rectangular pen 

putting value of 


to maximize 



but the dimensions must be lesser or equal to than that of barn.
therefore maximum length rectangular pen 
width of rectangular pen 
Maximum area of rectangular pen 
Hence maximum area of rectangular pen is
and dimensions are 
We have a trapezoid and a triangle
area of trapezoid=(base1+base2) times 1/2height
area of traingle=1/2 base times height
triangle
base=18
height=12
area=1/2 times 12 times 18=108
trapezoid
to find height we do
17=12+height
subtrac 12
5=height
so
base1=14
base2=18
height=5
area=(14+18) times 1/2 times 5
area=32 times 1/2 times 5
area=80
total area=area of trapezoid+area of triangle
total area=80+108
total area=188 mm^2
Answer:
the first one is 150
the second one is 2205
(and no one is stupid on here some people understand stuff and some don't, so yeah I don't think your stupid:-))
Answer: 1360 cubic meter
Step-by-step explanation:
Volume of solid= Length*width*height
=8*17*10
=1360 cubic meter