A because if you use T3 it wouldn’t have make sense so only reasonable and solution that works is A
Answer:
<u>Equation: V = C * (1 - r)^t</u>
<u>Answer: $ 8,066.37</u>
Step-by-step explanation:
Let's recall that depreciation on a car can be determined by the formula:
V = C * (1 - r)^t , where:
V is the value of the car after t years,
C is the original cost
r is the rate of depreciation
t is the number of years of utilization of the car
Therefore, we have:
V = C * (1-r)^t
V = 15,500 * (1 - 0.07)⁹
V = 8,066.37 (rounding to the next cent)
Answer:
All of the above
Step-by-step explanation:
dy/dt = y/3 (18 − y)
0 = y/3 (18 − y)
y = 0 or 18
d²y/dt² = y/3 (-dy/dt) + (1/3 dy/dt) (18 − y)
d²y/dt² = dy/dt (-y/3 + 6 − y/3)
d²y/dt² = dy/dt (6 − 2y/3)
d²y/dt² = y/3 (18 − y) (6 − 2y/3)
0 = y/3 (18 − y) (6 − 2y/3)
y = 0, 9, 18
y" = 0 at y = 9 and changes signs from + to -, so y' is a maximum at y = 9.
y' and y" = 0 at y = 0 and y = 18, so those are both asymptotes / limiting values.
Yes because if you answer both you get the same answer
This is just like working with money in a bank account
that's earning 12% interest.
If the population is 422,000 today, and
' n ' is the number of years after today,
then
Population = 422,000 (1.12)ⁿ .
