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Ilya [14]
3 years ago
11

Find the missing side lengths. WILL GIVE BRAINLIEST

Mathematics
1 answer:
kolezko [41]3 years ago
8 0
The missing side length is pigment because it is Pepe popo
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HELP PLEASE!! I NEED HELP ASAP!
Alex73 [517]

Answer:

4. A

5. B

Step-by-step explanation:

4. I'll solve question four first:

The two marked points on the line are (-2, -3)&(2, 5). Using the formula to find slope(y2-y1/x2-x1), substitute in the points.

5--3/2--2 or 8/4;simplified to 2/1 or 2.

Now use point-slope form: y-y1 = m(x-x1)

y--3 = 2(x--2): Substitute in the values of y1, m, and x1.

y+3 = 2x + 4: Distribute.

y = 2x + 1: Subtract three from both sides.

5. Do the same for question 5.

The first point is (-4, 2), the second point is (4, -1).

-1-2/4--4; -3/8.

Now use point-slope form:

y-2 = -3/8x -12/8: Substitute in the values of x1, y1, m, and distribute the slope to the parentheses.

y = -3/8x + 1/2

7 0
2 years ago
Need help with this test plz n thanks
Nastasia [14]
1+1 = 2
So if it is 2 then 2+6 = 8
I hope this helped love
7 0
3 years ago
Express the area A of a circle as a function of its​ radius, r. Determine the area of a circle whose radius is 11 inches. That​
nekit [7.7K]
<h2>Answer with explanation:</h2>

The function represents the area of a circle(A) is given by :-

A(r)=2\pi r

To determine the area of a circle whose radius is 11 inches. , we put the value of r=11 inches, we get

A(11)=2\pi (11)

Now, we put \pi=\dfrac{22}{7} in the above function , we get

A(11)=2(\dfrac{22}{7} )(11)\\\\\Rightarrow\ A=56.5714285714\approx56.57

8 0
3 years ago
2+8+5+9+90=<br>3+45+111=​
Anastasy [175]

Answer:

1) 114

2) 159

Step-by-step explanation:

2+8+5+9+90 = 114

3+45+111 = 159

Hope this helps.

8 0
3 years ago
Use the parabola tool to graph the quadratic function.<br><br> f(x)=2x^2+12x+16
viva [34]
The first thing you should know is that you need three points to be able to graph a second degree equation.
 You can create a table and plot several points to obtain the parabola
 In this case we will use a computational tool called wolfram alpha
 Answer: 
 See attached image.
 The graph is shown for two different intervals of the domain.

7 0
3 years ago
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