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Aloiza [94]
3 years ago
8

Which equation represents the line shown in the graph?

Mathematics
1 answer:
sweet [91]3 years ago
3 0
I don’t understand? Can u put like a picture and I’ll try to answer through the comments
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X^3-13x^2+40x=0 quadratic
777dan777 [17]

Answer:

x(x-5)(x-8)

or  

x=5

x=8

Step-by-step explanation:

x(x^2-13x+40)

x(x-5) (x-8)

6 0
3 years ago
Use the drawing tool(s) to form the correct answers on the provided graph.
Vera_Pavlovna [14]

Answer:

h( x ) = ( x + 1 )^2 - 4 x(h)×(÷×1)^2-4

3 0
3 years ago
Read 2 more answers
A piano has 52 white keys. Write and use an equation to find the number of octaves on a piano keyboard.
Firdavs [7]
There are 7 keys in each octave (C,D,E,F,G,A and B) so it would make sense to divide 52 to 7.
52/7=7 octaves and 3 extra kets
3 0
2 years ago
A ship travels 62.5 km in 1st hour of sailing. Starting from 2nd hour, the distance travelled per hour is x% of that in the prec
Bas_tet [7]
Speed of the ship in the second hour =  (62.5 * x ) / 100  kph.

In third hour it is  [(62 * x) / 100 ] * x/100]

is 4th hour its is the above * x/100 again  so we can now form the equation

62.5x      x          x
------- *   ----  *  ----    =  32
100      100      100

62,5 x^3 = 32,000,000
x^3 =  512,000
x = 80 <-----  Answer  to (a)

(b)  Ship travels 62.5 in first hour then  this falls by a common ratio of 0.8 each hour so we have a geometric sequence 

Dist travelled in 6 hours  =  a1  1 - r^n
                                                --------  = 62.5* (1 - 0.8^6) / 1 -0.8 = 230.56

                                               1 - r

Answer is    230.56 km 




5 0
3 years ago
A pile of earth removed from an excavation is a cone measuring 6ft high and 30ft across its base. How many trips will it take to
nignag [31]

Answer: 14

Step-by-step explanation:

Given

Excavation cone measures

height h=6\ ft

Diameter d=30\ ft

Truck can dump 125\ ft^3 at a time

The volume of a cone is

V=\dfrac{1}{3}\pi r^2h

Putting values

\Rightarrow V=\dfrac{1}{3}\times \pi\times 15^2\times 6\\\Rightarrow V=1413.9\approx 1414\ ft^3

No of trips(N) required to accumulate this much volume is given by

\Rightarrow N=\dfrac{1414}{125}=13.3\approx 14

Therefore, 14 trips are necessary to accumulate a cone of volume 1414\ ft^3

8 0
2 years ago
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